Several ice cubes (ρi = 0.9167 g/cm3) of total volume Vi = 225 cm3 and temperature 273.15 K (0.000 °C) are put into a thermos containing Vt = 660 cm3 of tea at a temperature of 313.15 K, completely filling the thermos. The lid is then put on the thermos to close it. Assume that the density and the specific heat of the tea is the same as it is for fresh water (ρw = 1.00 g/cm3, c = 4186 J/kgK). A: Calculate the amount of heat energy Qm in J needed to melt the ice cubes (Lf = 334 kJ/kg). B: Calculate the equilibrium temperature TE in K of the final mixture of tea and water. C: Calculate the magnitude of the total heat transferred QT in J from the tea to the ice cubes.
Latent heat and phase change
A physical process in which a conversion among the basic states or phases of matter, i.e., solid, liquid, and gas takes place under the effect of a certain temperature and pressure is referred to as a phase change. Generally, the phase change of a substance occurs when heat transfer takes place between the substance and its surroundings. Based on the direction in which heat transfer takes place, different types of phase changes can occur.
Triple Point of Water
The branch of physics in which observer deals with temperature related properties is called thermodynamics.
Boiling Point of Water
Everyday examples of boiling is, boiling milk, heating water. One would have observed that when we heat water it goes through various stages and at one point bubbles show in water, and water keeps splashing with bubbles bursting, we in layman terms say that water is boiling.
Freezing Point of Water
In general, the freezing point of water is 0° Celsius, or 32° Fahrenheit. This is the temperature at which water will ordinarily change from its liquid state to its solid state (ice). However, there are certain conditions that can affect the freezing point of water. For example, a liquid may be supercooled or contain impurities so that it does not freeze at the ordinary freezing point.
Several ice cubes (ρi = 0.9167 g/cm3) of total volume Vi = 225 cm3 and temperature 273.15 K (0.000 °C) are put into a thermos containing Vt = 660 cm3 of tea at a temperature of 313.15 K, completely filling the thermos. The lid is then put on the thermos to close it. Assume that the density and the specific heat of the tea is the same as it is for fresh water (ρw = 1.00 g/cm3, c = 4186 J/kgK).
A: Calculate the amount of heat energy Qm in J needed to melt the ice cubes (Lf = 334 kJ/kg).
B: Calculate the equilibrium temperature TE in K of the final mixture of tea and water.
C: Calculate the magnitude of the total
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