A 50.00-mL aliquot of a solution containing 0.0400 M Fe(NH4)2(SO4)2 is titrated with 0.0500 M Ce(SO4)2. Calculate the potential of the indicator cathode with respect to an SCE reference electrode after addition of 42.00 mL of cerium(IV). Given: E°(Ce4*/Ce3*) = 1.44 V, E (Fe3*/Fe2*) = 0.771 V

A 50.00-mL aliquot of a solution containing 0.0400 M Fe(NH4)2(SO4)2 is titrated with 0.0500 M Ce(SO4)2. Calculate the potential of the indicator cathode with respect to an SCE reference electrode after addition of 42.00 mL of cerium(IV). Given: E°(Ce4/Ce3) = 1.44 V, E (Fe3/Fe2) = 0.771 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A 50.00-mL aliquot of a solution containing 0.0400 M Fe(NH4)2(SO4)2 is titrated with 0.0500 M Ce(SO4)2. Calculate the potential of the indicator cathode with respect to an
SCE reference electrode after addition of 42.00 mL of cerium(IV). Given: E(Ce4*/Ce3*) = 1.44 V, E'(Fe3*/Fe2*) = 0.771 V
O 1.12 V
O 0.91 V
O 2.21 V
O 1.71 V
O 1.36 V

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