A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L = 845 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the polynomial T = A + By+ Cy2 through these points, the following approximate relation has been obtained. T= 46.7 x 10y-6.67 × 10122 Determine the magnitude T of torque applied to the shaft using this relation and the two equations given below. Y = Ty = PY L 2π] ρ?τὰρ

Elements Of Electromagnetics
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A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L =
845 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the
polynomial T = A + By+ Cy2 through these points, the following approximate relation has been obtained.
T= 46.7 x 10y-6.67 × 10122
Determine the magnitude T of torque applied to the shaft using this relation and the two equations given below.
P4
Y =
Ty = 2π] ρ?τὰρ
7 (MPa)
100
80
60
40
20
0
0,001 0.002 0.003 Y
d = 50 mm
"K
The magnitude T of torque applied to the shaft is
KN-m.
A²
Transcribed Image Text:A 50-mm diameter cylinder is made of a brass for which the stress-strain diagram is as shown. The angle of twist is 5° in a length L = 845 mm. The three points on the nonlinear stress-strain diagram used are (0, 0), (0.0015, 55 MPa), and (0.003, 80 MPa). By fitting the polynomial T = A + By+ Cy2 through these points, the following approximate relation has been obtained. T= 46.7 x 10y-6.67 × 10122 Determine the magnitude T of torque applied to the shaft using this relation and the two equations given below. P4 Y = Ty = 2π] ρ?τὰρ 7 (MPa) 100 80 60 40 20 0 0,001 0.002 0.003 Y d = 50 mm "K The magnitude T of torque applied to the shaft is KN-m. A²
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