A 5.0 m solid iron rod is at 25°C. How long would it take sound to move through the rod from one end to another? ○ 4.5 × 10-³ s 0 9.7 x 10-4 s S
A 5.0 m solid iron rod is at 25°C. How long would it take sound to move through the rod from one end to another? ○ 4.5 × 10-³ s 0 9.7 x 10-4 s S
University Physics Volume 1
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Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Interference of sound
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A seiche is an oscillating standing wave in a body of water. The term seiche pronounced saysh) can be understood by the sloshing of water back and forth in a swimming pool. The same phenomenon happens on a much larger scale in vast bodies of water including bays and lakes. A seizure can happen in any enclosed or semi-enclosed body of water.
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Which is the correct option?
![### Sound Propagation in Solids
#### Problem Statement
A 5.0 m solid iron rod is at 25°C. How long would it take sound to move through the rod from one end to another?
#### Instructions
You may use a calculator.
#### Multiple Choice Answers
- ○ \( 4.5 \times 10^{-3} \) s
- ○ \( 9.7 \times 10^{-4} \) s
- ○ \( 4.2 \times 10^{-4} \) s
- ○ \( 2.9 \times 10^{-4} \) s
#### Additional Information
**Speed of Sound Waves in Various Mediums**
Sound travels at different speeds through different materials. For precise calculations, knowing the speed of sound in the specific medium is necessary. Below is a table that provides the speed of sound through various mediums (at standard temperature and pressure conditions):
| Medium | Speed (m/s) |
|---------------|---------------|
| Air | 343 |
| Water | 1482 |
| Wood | 3850 |
| Iron | 5120 |
#### Explanation
To solve this problem, use the relationship between distance, speed, and time, which is given by the formula:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
For a 5.0 m iron rod:
- Distance (d) = 5.0 meters
- Speed of sound in iron (v) = 5120 meters/second
Thus, the time (t) it takes for sound to travel the length of the rod is:
\[ t = \frac{d}{v} = \frac{5.0 \text{ m}}{5120 \text{ m/s}} \]
This calculation results in:
\[ t \approx 9.77 \times 10^{-4} \text{ seconds} \]
Thus, the correct answer from the multiple choices is:
- ○ \( 9.7 \times 10^{-4} \) s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8dc949f-7f1d-4c1b-9c4e-dfcc47554f56%2F3ba620cf-c775-4c89-b555-b2ae306cdcf0%2F6ssw4ep_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Sound Propagation in Solids
#### Problem Statement
A 5.0 m solid iron rod is at 25°C. How long would it take sound to move through the rod from one end to another?
#### Instructions
You may use a calculator.
#### Multiple Choice Answers
- ○ \( 4.5 \times 10^{-3} \) s
- ○ \( 9.7 \times 10^{-4} \) s
- ○ \( 4.2 \times 10^{-4} \) s
- ○ \( 2.9 \times 10^{-4} \) s
#### Additional Information
**Speed of Sound Waves in Various Mediums**
Sound travels at different speeds through different materials. For precise calculations, knowing the speed of sound in the specific medium is necessary. Below is a table that provides the speed of sound through various mediums (at standard temperature and pressure conditions):
| Medium | Speed (m/s) |
|---------------|---------------|
| Air | 343 |
| Water | 1482 |
| Wood | 3850 |
| Iron | 5120 |
#### Explanation
To solve this problem, use the relationship between distance, speed, and time, which is given by the formula:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
For a 5.0 m iron rod:
- Distance (d) = 5.0 meters
- Speed of sound in iron (v) = 5120 meters/second
Thus, the time (t) it takes for sound to travel the length of the rod is:
\[ t = \frac{d}{v} = \frac{5.0 \text{ m}}{5120 \text{ m/s}} \]
This calculation results in:
\[ t \approx 9.77 \times 10^{-4} \text{ seconds} \]
Thus, the correct answer from the multiple choices is:
- ○ \( 9.7 \times 10^{-4} \) s
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