À = 4x-7y Given the two vectors, find the dot product and the angle between them. A = 4x-7 y and B = -3ê + 2ŷ – 5ê

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Chapter1: Units, Trigonometry. And Vectors
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**Problem 4:**

*Given the two vectors, find the dot product and the angle between them.*

\[ \vec{A} = 4\hat{x} - 7\hat{y} \]

\[ \vec{B} = -3\hat{x} + 2\hat{y} - 5\hat{z} \] 

In this problem, we need to compute the dot product of vectors \(\vec{A}\) and \(\vec{B}\), and subsequently determine the angle between these two vectors. The vectors \(\vec{A}\) and \(\vec{B}\) are described in terms of their components along the \(\hat{x}\), \(\hat{y}\), and \(\hat{z}\) axes. 

### Steps to Solve:

1. **Dot Product Calculation:**
   - The dot product formula for two vectors \(\vec{A} = a_1\hat{x} + a_2\hat{y} + a_3\hat{z}\) and \(\vec{B} = b_1\hat{x} + b_2\hat{y} + b_3\hat{z}\) is:
     \[ \vec{A} \cdot \vec{B} = a_1b_1 + a_2b_2 + a_3b_3 \]
   - Substitute the given values into the formula.

2. **Angle Between Vectors:**
   - Use the formula for the angle \(\theta\) between two vectors:
     \[ \cos \theta = \frac{\vec{A} \cdot \vec{B}}{|\vec{A}| |\vec{B}|} \]
   - Calculate the magnitudes of \(\vec{A}\) and \(\vec{B}\):
     \[ |\vec{A}| = \sqrt{(a_1)^2 + (a_2)^2 + (a_3)^2} \]
     \[ |\vec{B}| = \sqrt{(b_1)^2 + (b_2)^2 + (b_3)^2} \]
   - Solve for \(\theta\).

Provide detailed calculations and solutions for each step when using this material on an educational website.
Transcribed Image Text:**Problem 4:** *Given the two vectors, find the dot product and the angle between them.* \[ \vec{A} = 4\hat{x} - 7\hat{y} \] \[ \vec{B} = -3\hat{x} + 2\hat{y} - 5\hat{z} \] In this problem, we need to compute the dot product of vectors \(\vec{A}\) and \(\vec{B}\), and subsequently determine the angle between these two vectors. The vectors \(\vec{A}\) and \(\vec{B}\) are described in terms of their components along the \(\hat{x}\), \(\hat{y}\), and \(\hat{z}\) axes. ### Steps to Solve: 1. **Dot Product Calculation:** - The dot product formula for two vectors \(\vec{A} = a_1\hat{x} + a_2\hat{y} + a_3\hat{z}\) and \(\vec{B} = b_1\hat{x} + b_2\hat{y} + b_3\hat{z}\) is: \[ \vec{A} \cdot \vec{B} = a_1b_1 + a_2b_2 + a_3b_3 \] - Substitute the given values into the formula. 2. **Angle Between Vectors:** - Use the formula for the angle \(\theta\) between two vectors: \[ \cos \theta = \frac{\vec{A} \cdot \vec{B}}{|\vec{A}| |\vec{B}|} \] - Calculate the magnitudes of \(\vec{A}\) and \(\vec{B}\): \[ |\vec{A}| = \sqrt{(a_1)^2 + (a_2)^2 + (a_3)^2} \] \[ |\vec{B}| = \sqrt{(b_1)^2 + (b_2)^2 + (b_3)^2} \] - Solve for \(\theta\). Provide detailed calculations and solutions for each step when using this material on an educational website.
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