How would you do this one? In an engine, a piston oscillates so that its position at time t is given by h(t) = 5 cos(2t + 1/6),where distance is measured in centimeters and time is measured in seconds.Determine the average velocity of the piston on the interval [0.2 , 1.2].

The average velocity of the object is given by Where S = displacement of the object, t = total time takenThe position of the piston is given by Now at t = t1 = 0.2 s Thus the position of the piston At t = t2 = 1.2 s Thus the position of the piston The magnitude of the displacement of the object is S = |h2 - h1| S = |-4.881666 - 3.014765| S = 7.89643 cm Time interval t = t2 - t1 = 1.2 - 0.2 = 1.0 s The average velocity of the piston is given by The average velocity of the piston is = 7.89643 cm/s

Answered: In an engine, a piston oscillates so…

In an engine, a piston oscillates so that its position at time t is given by h(t) = 5 cos(2t + 7/6) where distance is measured in centimeters and time is measured in seconds. Determine the average velocity of the piston on the interval [0.2 , 1.2].