A block is hanging in equilibrium by two cables as shown below. The tension in the cables are T1 and T2. T1 = 50N. What is the mass of the block? 336N T2 50sin 50 30
A block is hanging in equilibrium by two cables as shown below. The tension in the cables are T1 and T2. T1 = 50N. What is the mass of the block? 336N T2 50sin 50 30
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I got 5.80kg for this one, I would like to double check if that's right.

Transcribed Image Text:### Problem:
A block is hanging in equilibrium by two cables as shown below. The tension in the cables are \( T_1 \) and \( T_2 \). \( T_1 = 50 \, \text{N} \). What is the mass of the block?
### Diagram Explanation:
- **Block and Cables Setup:**
- A block is suspended at a point by two cables.
- Cable \( T_1 \) makes an angle of \( 50^\circ \) with the horizontal and has a tension of 50 N.
- Cable \( T_2 \) makes an angle of \( 30^\circ \) with the horizontal.
- **Directions:**
- The \( +y \) direction is upwards, and the \( +x \) direction is to the right.
### Equations and Calculations:
- **Resolution of Forces:**
- Vertical components:
- \( T_{1y} = 50 \sin(50^\circ) \)
- \( T_{2y} = T_2 \sin(30^\circ) \)
- Horizontal components:
- \( T_{1x} = 50 \cos(50^\circ) \)
- \( T_{2x} = T_2 \cos(30^\circ) \)
- **Equilibrium Conditions:**
- Sum of vertical forces: \( T_{1y} + T_{2y} = mg \)
- Sum of horizontal forces: \( T_{1x} = T_{2x} \)
- **Given Calculations:**
- \( T_1 = 50 \, \text{N} \)
- Calculated \( T_2 = 37.11 \, \text{N} \) (not shown in detail)
### Objective:
Using the given tensions and angles, apply the conditions of equilibrium to find the mass \( m \) of the block by resolving these into their vertical components.
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