A 4.32-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest a = 0. Fx (N) n 2 4 6 8 10 12 14 16 3 2 1 What is its speed at the following positions? (a) x = 5.00 m (b) x = 10.0 m m/s m/s x (m)
A 4.32-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest a = 0. Fx (N) n 2 4 6 8 10 12 14 16 3 2 1 What is its speed at the following positions? (a) x = 5.00 m (b) x = 10.0 m m/s m/s x (m)
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![A 4.32-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest at \( x = 0 \).
**Graph Explanation:**
- The graph shows the force \( F_x \) (in Newtons) on the y-axis versus position \( x \) (in meters) on the x-axis.
- The force increases linearly from \( 0 \, \text{N} \) at \( x = 0 \, \text{m} \) to \( 3 \, \text{N} \) at \( x = 4 \, \text{m} \).
- The force remains constant at \( 3 \, \text{N} \) from \( x = 4 \, \text{m} \) to \( x = 10 \, \text{m} \).
- The force then decreases linearly back to \( 0 \, \text{N} \) from \( x = 10 \, \text{m} \) to \( x = 14 \, \text{m} \).
- The force remains \( 0 \, \text{N} \) from \( x = 14 \, \text{m} \) to \( x = 16 \, \text{m} \).
**What is its speed at the following positions?**
(a) \( x = 5.00 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]
(b) \( x = 10.0 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]
(c) \( x = 15.0 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c9a3da8-b443-4c7b-9ddb-d4ba4f71dd14%2Fdfdd1abb-533f-49e5-afbf-b66cf64b9a36%2F4fnfq8s_processed.png&w=3840&q=75)
Transcribed Image Text:A 4.32-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest at \( x = 0 \).
**Graph Explanation:**
- The graph shows the force \( F_x \) (in Newtons) on the y-axis versus position \( x \) (in meters) on the x-axis.
- The force increases linearly from \( 0 \, \text{N} \) at \( x = 0 \, \text{m} \) to \( 3 \, \text{N} \) at \( x = 4 \, \text{m} \).
- The force remains constant at \( 3 \, \text{N} \) from \( x = 4 \, \text{m} \) to \( x = 10 \, \text{m} \).
- The force then decreases linearly back to \( 0 \, \text{N} \) from \( x = 10 \, \text{m} \) to \( x = 14 \, \text{m} \).
- The force remains \( 0 \, \text{N} \) from \( x = 14 \, \text{m} \) to \( x = 16 \, \text{m} \).
**What is its speed at the following positions?**
(a) \( x = 5.00 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]
(b) \( x = 10.0 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]
(c) \( x = 15.0 \, \text{m} \)
\[ \_\_\_\_\_\_\_\_\_\_ \ \text{m/s} \]
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