0.50 kg - = 1.5 m/s r= 0.95 m 2.0 m 1.9 m An engineer is working on a new roller coaster, and he begins by making a scale model. On this model, a car of total mass 0.50 kg moves with negligible friction along the track shown in the figure. The car is given an initial speed vo = 1.5 m/s at the top of the first hill of height 2.0 m. Point A is located at a height of 1.9 m at the top of the second hill, the upper part of which is a circular arc of radius 0.95 m. Calculate the magnitude of the force of the track on the car at point A А) 3.07 N 2.21 N 2.08 N 3.25 N

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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0.50 kg
- = 1.5 m/s
r= 0.95 m
2.0 m
1.9 m
An engineer is working on a new roller coaster, and he begins by making a scale model. On this model, a
car of total mass 0.50 kg moves with negligible friction along the track shown in the figure. The car is given
an initial speed vo = 1.5 m/s at the top of the first hill of height 2.0 m. Point A is located at a height of 1.9 m
at the top of the second hill, the upper part of which is a circular arc of radius 0.95 m.
Calculate the magnitude of the force of the track on the car at point A
А) 3.07 N
2.21 N
2.08 N
3.25 N
Transcribed Image Text:0.50 kg - = 1.5 m/s r= 0.95 m 2.0 m 1.9 m An engineer is working on a new roller coaster, and he begins by making a scale model. On this model, a car of total mass 0.50 kg moves with negligible friction along the track shown in the figure. The car is given an initial speed vo = 1.5 m/s at the top of the first hill of height 2.0 m. Point A is located at a height of 1.9 m at the top of the second hill, the upper part of which is a circular arc of radius 0.95 m. Calculate the magnitude of the force of the track on the car at point A А) 3.07 N 2.21 N 2.08 N 3.25 N
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