A skier weighing 0.85 kN goes over a frictionless circular hill as shown. If the skier's speed at point A is 8.8 m/s, what is his speed at the top of the hill (point B)?

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A skier weighing 0.85 kN goes over a frictionless circular hill as shown. If the skier's speed at point A is 8.8 m/s, what is his speed at the top of the hill (point B)?

### Diagram Explanation

The image depicts a hill with a curved surface. Two points are labeled on this surface: point A and point B. 

- **Point B** is positioned at the peak of the hill directly above the base, with a vertical height of 10 meters from the ground.
- From point A, a dashed line extends downward, forming a right triangle with the vertical height. This dashed line makes a 45° angle with the horizontal line from the base to point B.

The diagram is likely illustrating a concept related to trigonometry in physics, such as calculating potential energy, projectile motion, or slope analysis. The 45° angle can be significant in analyzing components of forces, velocities, or motion parameters in physics problems.
Transcribed Image Text:### Diagram Explanation The image depicts a hill with a curved surface. Two points are labeled on this surface: point A and point B. - **Point B** is positioned at the peak of the hill directly above the base, with a vertical height of 10 meters from the ground. - From point A, a dashed line extends downward, forming a right triangle with the vertical height. This dashed line makes a 45° angle with the horizontal line from the base to point B. The diagram is likely illustrating a concept related to trigonometry in physics, such as calculating potential energy, projectile motion, or slope analysis. The 45° angle can be significant in analyzing components of forces, velocities, or motion parameters in physics problems.
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