A 4-foot square footing has its bottom 2.24 ft. below the ground surface. The ground water table is located at a depth of 4 ft. below the ground surface. Unit weight of soil is 113 lb/ft3, Saturated unit weight is 123 lb/ft3, cohesion = 90 lb/ft2. Use angle of internal friction = 30° (Nc = 35.7, Nq = 29.7, N = 19.0). Compute the allowable load (in lb) that the footing could carry. Use FS = 2.4.
A 4-foot square footing has its bottom 2.24 ft. below the ground surface. The ground water table is located at a depth of 4 ft. below the ground surface. Unit weight of soil is 113 lb/ft3, Saturated unit weight is 123 lb/ft3, cohesion = 90 lb/ft2. Use angle of internal friction = 30° (Nc = 35.7, Nq = 29.7, N = 19.0). Compute the allowable load (in lb) that the footing could carry. Use FS = 2.4.
Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter16: Shallow Foundations-bearing Capacity
Section: Chapter Questions
Problem 16.19CTP: A 2.0 m 2.0 m square pad footing will be placed in a normally consolidated clay soil to carry a...
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![A 4-foot square footing has its bottom 2.24 ft. below the ground surface. The ground water table is located at a depth of 4 ft. below the ground surface. Unit weight of soil is 113 lb/ft3, Saturated
unit weight is 123 lb/ft3, cohesion = 90 lb/ft2. Use angle of internal friction = 30° (Nc = 35.7, Nq = 29.7, N = 19.0).
Compute the allowable load (in lb) that the footing could carry. Use FS = 2.4.
Round off to the nearest whole number.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7841618c-c4a5-4219-81ff-992d23847a12%2F8ef3c64e-4aa1-441e-a3ae-1b0fb3a0baad%2Fb4wgoao_processed.png&w=3840&q=75)
Transcribed Image Text:A 4-foot square footing has its bottom 2.24 ft. below the ground surface. The ground water table is located at a depth of 4 ft. below the ground surface. Unit weight of soil is 113 lb/ft3, Saturated
unit weight is 123 lb/ft3, cohesion = 90 lb/ft2. Use angle of internal friction = 30° (Nc = 35.7, Nq = 29.7, N = 19.0).
Compute the allowable load (in lb) that the footing could carry. Use FS = 2.4.
Round off to the nearest whole number.
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