A 32 pound object is suspended from a spring with spring coefficient 1 Ib/ft. The whole system is suspended in a viscous liquid that has a damping coefficient of 1 lb*sec/ft and subjected to an external force F(t) = 5 sin(2t) + cos(2t). Find a formula describing only the forced response of the object. Use only a single cosine in your answer. What is the formula for the forced response of the object? U(t) = help (formulas)
Q: A child bounces in a harness suspended from a door frame by three parallel elastic bands. (a) If…
A:
Q: A mass of 9.1 g is suspended from a massless spring of natural length 90 mm with the spring constant…
A:
Q: A block oscillating on a spring has period T = 2.4 s . Note: You do not know values for either m or…
A: Given:T=2.4 s
Q: The system shown in Figure Q1 consists of two interconnected masses mi and mz. Both springs of…
A: Since you have have asked multiple question, we will solve the first question for you. If you want…
Q: A square raft with edge length L = 2.7 m floats on a pond. You step on the raft, then dive off, and…
A:
Q: A spring with constant k = 5 N/m hanging from the ceiling is placed at its lower end with an object…
A:
Q: A damped oscillator has mass m=5.3 kg, spring constant k = 27 N/m, and viscous force constant c = 11…
A: Given that:mass Spring Constant Viscous Force Constant Amplitude of Driving Force: desired Threshold…
Q: A ball on a spring starts at its lowest point of 7 inches below equilibrium, bounces to its maximum…
A:
Q: A mass of 10 grams swings on a pendulum of length 2 meters. By marking the oscillations, you note…
A:
Q: The 15-kg block A has a velocity v = 15 m/s when it is s = 6 m from the 10-kg block B as shown in…
A:
Q: The force of a spring is given by F = −kx, where k is the stiffness of the spring and x is the…
A: The relation between force and potential energy is,
Q: A spring with spring constant k = 12 slug/s2 has a mass attached that stretches the spring 2-2/3 ft.…
A:
Q: A long limp spring is hung from a beam; the spring's bottom is 660 mm above the table. A 0.50 kg…
A: Concept: The weight is attached to the spring in the case of a spring mass system. The restoring…
Q: A certain ideal spring elongates 38.5 mm when it is suspended vertically and a block of mass M is…
A: Given, Elongation of spring x=38.5 mm =0.0385 m Mass of the block is M. By balancing the force we…
Q: Problem 2. A 3-foot spring measures 9 feet long after a mass weighing 12 pounds is attached to it.…
A: The Newton's second law for the system is m(d2x/dt2)=−kx−βdx/dt Where: m be the mass attached, k be…
Q: A mass weighing 14 pounds stretches a spring 2 feet. The mass is attached to a dashpot device that…
A:
Q: A mass m = 2.55 kg is at the end of a horizontal spring on a frictionless horizontal surface. The…
A: Mass of object (m) = 2.55 kg Amplitude of motion (A) = 2.5 cm = 0.025 m Frequency (f) = 1.05 Hz
Q: A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a…
A: Given information: The weight of the mass (m) = 4 lb The spring constant of the spring (k) = 2 lb/ft…
Q: You have a simple pendulum that consists of a small metal ball attached to a long string. You push…
A:
Q: You want to create the art installation in figure C, in which a block of mass 29.8 kg is hung with…
A:
Q: A block of mass m = 200 g is attached to a spring whose spring constant isk= 3.2 N/m. Thne block…
A:
Q: A 9.00 kg object oscillates at the end of a vertical spring that has a spring constant of 2.10 x 104…
A: As per given information, you have asked only part (b).
Q: A driving force of the form F(t) = (0.290 N) sin (2π ft) acts on a weakly damped spring oscillator…
A: The force equation: The mass of the damped oscillator: Spring constant: Damping constant:
Q: The cylinder is confined by the brake as shown in (Figure 1), where μ = 0.4. The spring has a…
A: Torque, T = 800 N.mUnstretched length, L = 60 mmCoefficient of static friction () = 0.4Spring…
Q: A mass m = 2.75 kg is at the end of a horizontal spring on a frictionless horizontal surface. The…
A: Given : Mass attached, m = 2.75 kg Amplitude of oscillation, A = 4.5 cm = 0.045 m Frequency of…
Q: A mass on the end of a spring oscillates with an amplitude of 35cm at a frequency of 20 Hz (cycles…
A:
Q: Consider a situation in which a pendulum made from a wooden sphere. The mass of the pendulum is 100…
A: Given : Mass of the pendulum, m =100 g=100×10-3 kg Length of the pendulum, l=1m Question :…
Q: A vertical spring is so that it's stretched 1/4 meter when a 1/2 kg mass is attached at the end of…
A: Given:mass attached to spring, m = 0.5 kgthe spring streches by d = 0.25 m to attain…
Q: M In a damped oscillator, let m = 250 g, k=85 N/m, and b=0.070 kg/s. In how many periods of…
A: Given, The mass, m=0.25 Kg The spring constant, k=85 N/m
Q: A spring oscillator is designed with a mass of 0.288 kg. It operates while immersed in a damping…
A:
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- A mass m = 3.3 kg is at the end of a horizontal spring on a frictionless horizontal surface. The mass is oscillating with an amplitude A = 4.5 cm and a frequency f = 1.5 Hz. a. Write an equation for the spring constant k. b. Calculate the spring constant k, in Newtons per meter. c. Write an equation for the total mechanical energy, E, of the motion. Your expression should be in terms of the variables in the original problem statement. d. Calculate the total mechanical energy E, in joules.By Hooke’s law, we know that the magnitude of the restoring force of a spring is Fs=kx, where k is the spring constant and x is the distance the spring stretches. We also know that the magnitude of the gravitational force is w=mg. Therefore, if we attach a weight to the end of a spring and allow it to hang in static equilibrium, these two forces must balance each other out. Find the equation that can be used to determine the spring constant k if a mass m is attached to the end of the spring, assuming you can measure m as well as the amount the spring stretches, x.8. A weight of 0.5kg stretches a spring by 0.49m. The spring-mass system is submerged in delicious melted butter with a damping coefficient of y=4. The spring is then lowered by an additional 1.0m and released with velocity 0. There is no external force. Find the function which gives the location of the weight at time t. Note: I have designed this to work out nicely. If it's not working out nicely then you probably got some butter in your calculations.
- A mass weighting 24 lbs stretches a spring 4 inches. The mass is in a medium that exerts a damping force of 57 lbs when the mass has a speed of 6 ft/sec. Suppose the object is displaced an additional 8 inches and released. Find an equation for the object's displacement, u(t), in feet after t seconds. u(t) = Use the convention: If the displacement is upward then u <0Ignoring friction, what will be the angular position of the pendulum at t = 0.35 s? A simple pendulum is 0.44 m long. At t = 0 it is released from rest starting at an angle of 18°. Express your answer in degrees. ΑΣφ ? O0.35 Submit Request Answer Part B Ignoring friction, what will be the angular position of the pendulum at t = 3.45 s? Express your answer in degrees. ? O3.45 %D Submit Request Answer Part C Ignoring friction, what will be the angular position of the pendulum at t = 6.00 s?Chapter 15, Problem 24 Z Your answer is partially correct. Try again. In the figure, two springs are joined and connected to a block of mass 40.3 kg that is set oscillating over a frictionless floor. The springs each have spring constant k = 242 N/m. What is the frequency (in Hz) of the oscillations? Number Units THz the tolerance is +/-2%
- A 3 kilogram weight stretches a spring by 8 cm. The mass-spring system is immersed in a damping fluid which exerts a force of 0.5 N when the mass is traveling 0.25 m/sec. Write a differential equation for u(t), the displacement of the mass at time t. (use g = 9.8 m/sec ^2 .)A 2-kg mass is attached to a spring hanging from the ceiling, thereby causing the spring to stretch 1.4 m upon coming to rest at equilibrium. At time t= 0, an external force of F(t) = cos 2t N is applied to the system. The damping constant for the system is 4 N-sec/m. Determine the steady-state solution for the system. The steady-state solution is y(t)=- plz helpA mass of 573 g is hanging underneath a spring which has an unknown spring constant. The period of oscillation is 2.64 seconds. Find the spring constant in N/m. Give your answer with a single digit of precision. Your Answer: Answer
- need help with dA 2-kg mass is attached to a spring with stiffness 56 N/m. The damping constant for the system is 8√√7 N-sec/m. If the mass is pulled 10 cm to the right of equilibrium and given an initial rightward velocity of 4 m/sec, what is the maximum displacement from equilibrium that it will attain?A mass of 4.6 g is suspended from a massless spring of natural length 90 mm with the spring constant k = 3 Nm and causes the spring to extend by 10 mm. The mass is pulled down a further 5 mm and then released. Assuming g = 9.8 ms2, calculate the period of simple harmonic motion of the mass. Give your answer in Sl units.