A 30 cm long cord is wrapped around the edge of an engine starter that has the same moment of inertia as a hoop. The mass of the starter is 450 g and a radius of 6 cm. If the cord starts from rest and is pulled completely off in 7 seconds, what torque is delivered to the starter?

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Chapter1: Units, Trigonometry. And Vectors
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**Problem:**

A 30 cm long cord is wrapped around the edge of an engine starter that has the same moment of inertia as a hoop. The mass of the starter is 450 g and a radius of 6 cm. If the cord starts from rest and is pulled completely off in 7 seconds, what torque is delivered to the starter?

**Solution Approach:**

1. **Identify Known Values:**
   - Length of cord (s) = 30 cm = 0.3 m
   - Mass of starter (m) = 450 g = 0.45 kg
   - Radius of starter (r) = 6 cm = 0.06 m
   - Time (t) = 7 seconds

2. **Moment of Inertia:**
   - For a hoop, \( I = mr^2 \)
   - Compute \( I = 0.45 \, \text{kg} \times (0.06 \, \text{m})^2 \)

3. **Angular Acceleration:**
   - Use \( \theta = \frac{1}{2} \alpha t^2 \) to find angular acceleration (\(\alpha\))
   - Convert linear length to angular distance: \( \theta = \frac{0.3 \, \text{m}}{0.06 \, \text{m}} \)

4. **Torque Calculation:**
   - Torque (\(\tau\)) = \( I \times \alpha \)

By using these steps, determine the torque delivered to the starter.
Transcribed Image Text:**Problem:** A 30 cm long cord is wrapped around the edge of an engine starter that has the same moment of inertia as a hoop. The mass of the starter is 450 g and a radius of 6 cm. If the cord starts from rest and is pulled completely off in 7 seconds, what torque is delivered to the starter? **Solution Approach:** 1. **Identify Known Values:** - Length of cord (s) = 30 cm = 0.3 m - Mass of starter (m) = 450 g = 0.45 kg - Radius of starter (r) = 6 cm = 0.06 m - Time (t) = 7 seconds 2. **Moment of Inertia:** - For a hoop, \( I = mr^2 \) - Compute \( I = 0.45 \, \text{kg} \times (0.06 \, \text{m})^2 \) 3. **Angular Acceleration:** - Use \( \theta = \frac{1}{2} \alpha t^2 \) to find angular acceleration (\(\alpha\)) - Convert linear length to angular distance: \( \theta = \frac{0.3 \, \text{m}}{0.06 \, \text{m}} \) 4. **Torque Calculation:** - Torque (\(\tau\)) = \( I \times \alpha \) By using these steps, determine the torque delivered to the starter.
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