inertia of a disc is I = MR² F₁ = 2.5 N applied at the outer edge of the disc. F2 = 5.1 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?
inertia of a disc is I = MR² F₁ = 2.5 N applied at the outer edge of the disc. F2 = 5.1 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?
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Transcribed Image Text:A circular disk with a radius of 0.51 m is subject to
2 tangentially applied forces. The disc is fixed
such that it will rotate about its center. Both
forces produce a torque in the same direction.
The mass of the disc is 0.58 kg. The moment of
inertia of a disc is I = MR²
F₁ = 2.5 N applied at the outer edge of the disc.
F₂ = 5.1 N applied at a distance of 0.29 from the
center of the disc.
What is the angular acceleration of the disc?
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