A circular disk with a radius of 0.51 m is subject to2 tangentially applied forces. The disc is fixedsuch that it will rotate about its center. Bothforces produce a torque in the same direction.The mass of the disc is 0.58 kg. The moment ofinertia of a disc is I = MR²F₁ = 2.5 N applied at the outer edge of the disc.F₂ = 5.1 N applied at a distance of 0.29 from thecenter of the disc.What is the angular acceleration of the disc?

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Answered: inertia of a disc is I = MR² F₁ = 2.5 N…

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inertia of a disc is I = MR² F₁ = 2.5 N applied at the outer edge of the disc. F2 = 5.1 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?