A circular disk with a radius of 0.36 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.68 kg. The moment of inertia of a disc is I = ( 1 / 2 ) MR ^ 2 F1 = 3.1 N applied at the outer edge of the disc. F2 = 4.6 N applied at a distance of 0.27 from the center of the disc. What is the angular acceleration of the disc?

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A circular disk with a radius of 0.36 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.68 kg. The moment of inertia of a disc is = ( 1 / 2 ) MR ^ 2

F1 = 3.1 N applied at the outer edge of the disc.

F2 = 4.6 N applied at a distance of 0.27 from the center of the disc.

What is the angular acceleration of the disc?

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