A 3.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point P in the figure (Figure 1). Part C If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant? Express your answer in kilogram-meters squared per second squared.

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Chapter1: Units, Trigonometry. And Vectors
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I only need part C, thank you

A 3.80 kg rock has a horizontal velocity of magnitude
12.0 m/s when it is at point P in the figure (Figure 1).
Part C
If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant?
Express your answer in kilogram-meters squared per second squared.
?
TP
dt
= 178.877
kg - m2 /s?
Figure
< 1 of 1
12.0 m/s
Part D
What is the direction of the rate in part (C)?
8.00 m
into the page
O out of the page
36.9
Transcribed Image Text:A 3.80 kg rock has a horizontal velocity of magnitude 12.0 m/s when it is at point P in the figure (Figure 1). Part C If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant? Express your answer in kilogram-meters squared per second squared. ? TP dt = 178.877 kg - m2 /s? Figure < 1 of 1 12.0 m/s Part D What is the direction of the rate in part (C)? 8.00 m into the page O out of the page 36.9
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