A 3.5-kg block is placed between two horizontal springs. Neither spring is strained when the block is located at the position labeled x = Om in the drawing. The block is then displaced a distance of 0.070 m from the position where x = 0 m and released from rest. (a) What is the speed of the block when it passes back through the x = 0 m position? (b) Determine the angular frequency w of this system. x=0m 0.070 m k = 450 N/m k= 650 N/m um

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A 3.5-kg block is placed between two horizontal springs. Neither spring is strained when the block is located at the position labeled x=0m in the drawing. The block is then displaced a distance of 0.070m from the position where x=0m and released from rest. (a) What is the speed of the block when it passes back through the x=0m position? (b) Determine the angular frequency w of this system.

### Problem Statement:

A 3.5-kg block is placed between two horizontal springs. Neither spring is strained when the block is located at the position labeled \(x = 0 \text{ m}\) in the drawing. The block is then displaced a distance of \(0.070 \text{ m}\) from the position where \(x = 0 \text{ m}\) and released from rest. 

(a) What is the speed of the block when it passes back through the \(x = 0 \text{ m}\) position?  
(b) Determine the angular frequency \(\omega\) of this system.

### Diagram Description:

The diagram shows a block placed between two horizontal springs. The spring on the left has a spring constant \(k = 450 \text{ N/m}\) and the spring on the right has a spring constant \(k = 650 \text{ N/m}\). The block is initially at the position \(x = 0 \text{ m}\), which is marked in the center between the two springs. The block is displaced \(0.070 \text{ m}\) to the right from the equilibrium position. The springs are unstrained when the block is at the equilibrium position.

### Additional Explanation:

- The springs will exert forces proportional to their spring constants when the block is displaced from the equilibrium position.
- When released, the potential energy stored in the springs is converted into kinetic energy as the block returns to \(x = 0 \text{ m}\). 
- The angular frequency \(\omega\) provides information about the oscillation characteristics of the system, such as the rate of oscillation.
Transcribed Image Text:### Problem Statement: A 3.5-kg block is placed between two horizontal springs. Neither spring is strained when the block is located at the position labeled \(x = 0 \text{ m}\) in the drawing. The block is then displaced a distance of \(0.070 \text{ m}\) from the position where \(x = 0 \text{ m}\) and released from rest. (a) What is the speed of the block when it passes back through the \(x = 0 \text{ m}\) position? (b) Determine the angular frequency \(\omega\) of this system. ### Diagram Description: The diagram shows a block placed between two horizontal springs. The spring on the left has a spring constant \(k = 450 \text{ N/m}\) and the spring on the right has a spring constant \(k = 650 \text{ N/m}\). The block is initially at the position \(x = 0 \text{ m}\), which is marked in the center between the two springs. The block is displaced \(0.070 \text{ m}\) to the right from the equilibrium position. The springs are unstrained when the block is at the equilibrium position. ### Additional Explanation: - The springs will exert forces proportional to their spring constants when the block is displaced from the equilibrium position. - When released, the potential energy stored in the springs is converted into kinetic energy as the block returns to \(x = 0 \text{ m}\). - The angular frequency \(\omega\) provides information about the oscillation characteristics of the system, such as the rate of oscillation.
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