5.0m feeeeeA mass m = 25 kg is sitting on a slope with = 20°.There is no friction between the mass and the slope.The mass is attached to a spring with rest lengthlo = 5 cm that is mounted at the top of the slope.When the mass is released, the spring stretches anamount Ax = 6.2 cm (as measured along the slope,total length is now 11.2 cm) when the system reachesstatic equilibrium.a.) Draw the free-body diagram of the mass, showingall forces acting on the mass.b.) Calculate the value of the spring constant, k.

Solution:-Given thatm=25 kg, θ=20°, lo=5 cm∆x=6.2 cm=0.062 m

Answered: 5. 0 m feeler A mass m = 25 kg is…

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