A 3.0 kg toy car can move along an x axis. The figure gives Fx of the force acting on the car, which begins at rest at time t = 0. The scale on the Fy axis is set by Fys = 3.0 N. In unit-vector notation, what is P at (a)t = 9.0 s and (b)t = 5.0 s,(c) what is v att= 3.0 s? F, (N) F t (s) -F

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement

A 3.0 kg toy car can move along an x-axis. The figure gives \( F_x \) of the force acting on the car, which begins at rest at time \( t = 0 \). The scale on the \( F_x \) axis is set by \( F_{xs} = 3.0 \, \text{N} \). In unit-vector notation, what is \( \vec{P} \) at:

- (a) \( t = 9.0 \, \text{s} \)
- (b) \( t = 5.0 \, \text{s} \)
- (c) what is \( \vec{v} \) at \( t = 3.0 \, \text{s} \)?

### Graph Explanation

The graph on the right shows \( F_x \) (in Newtons) plotted against time \( t \) (in seconds). The force \( F_x \) varies with time as follows:

- From \( t = 0 \) to \( t = 2 \, \text{s} \), \( F_x \) increases linearly.
- From \( t = 2 \, \text{s} \) to \( t = 4 \, \text{s} \), \( F_x \) remains constant.
- From \( t = 4 \, \text{s} \) to \( t = 6 \, \text{s} \), \( F_x \) decreases linearly.
- From \( t = 6 \, \text{s} \) to \( t = 8 \, \text{s} \), \( F_x \) becomes negative, indicating a reversal of the direction of force.

### Solution Form

Respond with the values for \( \vec{P} \) and \( \vec{v} \) in the following format:

- (a) Number [input box] \( \hat{i} \) + Number [input box] \( \hat{j} \) + Number [input box] \( \hat{k} \) [Units dropdown]
- (b) Number [input box] \( \hat{i} \) + Number [input box] \( \hat{j} \) + Number [input box] \( \hat{k} \) [Units dropdown]
- (c) Number [input box] \( \hat{i
Transcribed Image Text:### Problem Statement A 3.0 kg toy car can move along an x-axis. The figure gives \( F_x \) of the force acting on the car, which begins at rest at time \( t = 0 \). The scale on the \( F_x \) axis is set by \( F_{xs} = 3.0 \, \text{N} \). In unit-vector notation, what is \( \vec{P} \) at: - (a) \( t = 9.0 \, \text{s} \) - (b) \( t = 5.0 \, \text{s} \) - (c) what is \( \vec{v} \) at \( t = 3.0 \, \text{s} \)? ### Graph Explanation The graph on the right shows \( F_x \) (in Newtons) plotted against time \( t \) (in seconds). The force \( F_x \) varies with time as follows: - From \( t = 0 \) to \( t = 2 \, \text{s} \), \( F_x \) increases linearly. - From \( t = 2 \, \text{s} \) to \( t = 4 \, \text{s} \), \( F_x \) remains constant. - From \( t = 4 \, \text{s} \) to \( t = 6 \, \text{s} \), \( F_x \) decreases linearly. - From \( t = 6 \, \text{s} \) to \( t = 8 \, \text{s} \), \( F_x \) becomes negative, indicating a reversal of the direction of force. ### Solution Form Respond with the values for \( \vec{P} \) and \( \vec{v} \) in the following format: - (a) Number [input box] \( \hat{i} \) + Number [input box] \( \hat{j} \) + Number [input box] \( \hat{k} \) [Units dropdown] - (b) Number [input box] \( \hat{i} \) + Number [input box] \( \hat{j} \) + Number [input box] \( \hat{k} \) [Units dropdown] - (c) Number [input box] \( \hat{i
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