A 3-q, 150-kW, 2300-V, 50-Hz, 1000-rpm salient-pole synchronous motor has Xd = 32 N / phase and Xq = 20 N / phase. Neglecting losses, calculate the torque developed by the motor if field excitation is so adjusted as to make the back e.m.f. twice the applied voltage and a = 16°.
A 3-q, 150-kW, 2300-V, 50-Hz, 1000-rpm salient-pole synchronous motor has Xd = 32 N / phase and Xq = 20 N / phase. Neglecting losses, calculate the torque developed by the motor if field excitation is so adjusted as to make the back e.m.f. twice the applied voltage and a = 16°.
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter35: Harmonics 916
Section: Chapter Questions
Problem 3RQ: Would a positive-rotating harmonic or a negative-rotating harmonic be more harmful to an induction...
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![Problem 6:
A 3-q, 150-kW, 2300-V, 50-Hz, 1000-rpm salient-pole synchronous motor has Xd = 32 Q / phase
and Xq = 20 S / phase. Neglecting losses, calculate the torque developed by the motor if field
excitation is so adjusted as to make the back e.m.f. twice the applied voltage and a = 16°.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabb7c75e-40cc-40b3-89f4-34bec7edbaa1%2F596586b3-2329-451f-a117-ac73e637d5e0%2F97gzzvl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 6:
A 3-q, 150-kW, 2300-V, 50-Hz, 1000-rpm salient-pole synchronous motor has Xd = 32 Q / phase
and Xq = 20 S / phase. Neglecting losses, calculate the torque developed by the motor if field
excitation is so adjusted as to make the back e.m.f. twice the applied voltage and a = 16°.
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