Answered: A 3-m wide channel carries a total…

A 3-m wide channel carries a total discharge of 12 m³ s-!. Calculate: (a) the critical depth; (b) the minimum specific energy; (c) the alternate depths when E = 4 m.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Please answer fast.

Q: In rectangular channel at a section P, it is required that the depth of flow is to be 1.4 m and the…

A: Depth of flow (y)=1.4m Specific energy (E)=2.8m To find Flow condition subcritical, critical, or…

Q: Problem #3 Hydraulic Jump A hydraulic jump occurs in a rectangular channel 4.0 m wide. The water…

Q: Compute the specific energy (E) for a channel with a flow depth of 1.3 m, an average velocity of 0.8…

A: Given:Flow depth, y = 1.3 mAverage velocity, v = 0.8 m/sBed slope, S = 0.014 m/mRequired:Specific…

Q: nowing that the Froude number is equal to unity in critical flow condition, what is the critical…

A: Width B=3mDischarge(Q)=2.65m3/s

Q: What is the critical depth in a rectangular channel with 2.3 m width and 0.91 m2/s discharge per…

A: What is the critical depth in a rectangular channel and calculate minimum specific energy?

Q: A 1m wide rectangular channel carries a discharge of 2m³/s. The specific energy-depth diagram is…

Q: 8) A hydraulic jump is to be formed in a trapezoidal channel width a base width of 6 m and side…

Q: 3- A rectangular channel has a width of 5 m, carriers a discharge of 24 m³/s with a depth of 3.2 m…

Q: A hydraulic jump occurs in a trapezoidal channel with side slopes of 1:1 and base of 4 m. If the…

Q: Calculate the approximate specific energy of a trapezoidal channel having a bottom width of 5m,…

A: Given Data Bottom width (B) = 5m Side slope (1:m) = 1:1 Discharge (Q) = 15 m3/s Depth of flow (y)…

Q: A 3 m wide rectangular channel, as shown, carries a flow of 11.7m³/s. hydraulic jump Ус y2 2 Az =…

A: Given data: rectangular channel width = 3 m Discharge = 11.7 m3/s At section 3 hump = 0.4 m

Q: Q. 10. A rectangular channel 2m wide has a specific energy of 1.50m when carrying discharge of…

A: Given- A rectangular channel- Width B=2 m. Specific energy E=1.5 m Discharge Q=6.32 m3/s, It is…

Q: A single ideal pumping well, with radius of 1.0 ft and flow rate of 155 gpm, exists in an ideal…

Q: The conjugate depths at a location in a horizontal rectangular channel, 4m wide, are 0.2 m and 1.0…

Q: Water flows over a spillway that is 8 ft wide. If the flow is 450 ft^3/s, and the depth at the…

A: above given data we have to find Fe ant point 1 depth after hydraulic jump and energy that is lost

Q: A well pumps at a steady rate of 70gallons/minute (265L/min). It is located 50ft (15.2m) from a…

A: Discharge (Q) is given as 265L/min Diameter (d) is given as 15.2 cm Distance (D) is given as 15.2 m…

Q: A hydraulic jump is situated a 4 m wide rectangular channel. The discharge in the channel is 7.5…

Q: Problem 2: (a) Define: (i) specific energy (ii) Froude number For open-channel flow. What is special…

A: Disclaimer Since you have asked multiple questions, we will solve the first question for you. If you…

Concept explainers

Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.

Question

H.W. 1
A 3-m wide channel carries a total discharge of 12 m³ s- Calculate:
(a)
the critical depth;
(b)
the minimum specific energy;
the alternate depths when E = 4 m.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

The term alternate depths in open channel flow is used to designate the depths O at the beginning and end of a hydraulic jump. O at the beginning and end of a gradually varied flow profile. O having the same specific energy for a given discharge. O having same kinetic energy for a given discharge.
) A) Determine the critical depth in a trapezoidal channel for a discharge of 150 m3/sec. The width of the channel bottom is 6 m, and the side slop upward at angle of 4
Provide handwritten answer please
The trapezoidal channel below must maintain a discharge of Q = 20 x SN (m3/s). You may assume that the channel slope is negligible. Use MS Excel spreadsheet to plot the specific energy curve and determine the critical depth Dc. Hint: You should first set up a column of normal depth D (m) ranging from 0 to SN, and then calculate the area (A), velocity (V), energy (E) and Froude number (Fr). ***SN=21
A rectangular channel is 4 m wide, and it reduces to 2 m through a hydraulic structure. Assuring the transition to be horizontal and the flow to be frictionless determine the water surface elevations upstream of the constriction when the specific energy at the constriction is 6 m. Assume choking occurs, hence critical flow equations are applicable. Note: Hand written solution is not allowed.
A trapezoidal channel has a bottom width of 6m and side slope of 1:1. The depth of flow is 2m at a discharge of 24 m³/s. What would be the specific energy (take, g = 10m /(s^ 2))?
Figure: 1 b) Plot the specific energy versus depth curves (in normal graph paper) for Q = 400 and 800 m³/s in a trapezoidal channel having a bottom width of 20m and side slopes of 2H:1V. Assume the bottom slope is small. From these curves, determine the critical depth for each discharge.
Given The channel shown in the figure has a surface of float-finished concrete and is laid on a slope that falls 0.27 m per 100 m of length. Required Calculate the normal discharge for a depth of 1.5 m in m3/s, to the nearest 100th. 2 - 3.0 m
A) A fully penetrating unconfined well of 12 in. The diameter is pumped at a rate of 1 ft^3/sec. The coefficient of permeability is 750 gal/day per square foot. The drawdown in an observation well located 200 ft away from the pumping well is 10 ft below its original depth of 150 ft. Find the water level in the well. B) In addition to the requested information, calculate the radius of influence for the well (in ft). You will get an extremely large and unreasonable value (in the millions...pinky to corner of mouth required). C) Then develop a plot of the water surface profile for the well during pumping. Orient the plot so that the x-axis represents the distance from the production well (and looks like the bottom of the aquifer (i.e., the datum)) and the pumping well is represented by the y-axis and shows the water depth (in feet) in the aquifer. I recommend selecting small intervals (10-20 feet) of x-axis values between the y-axis and 500 feet. Then use increments of 1,000-1,000,000 as…
In a triangular channel, the critical depth for a discharge of 1.2 m³/s is 1.3 m. The critical depth. for a discharge of 38.4 m³/s through the same channel would be: (b) 2 1m
question attached.
I need the answer as soon as possible