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Figure: 1 Plot the specific energy versus depth curves (in normal graph paper) for Q = 400 and 800 m/s in a trapezoidal channel having a bottom width of 20m and side slopes of 2H:1V. Assume the bottom slope is small. From these curves, determine the critical depth for each discharge. %3D

Figure: 1 Plot the specific energy versus depth curves (in normal graph paper) for Q = 400 and 800 m/s in a trapezoidal channel having a bottom width of 20m and side slopes of 2H:1V. Assume the bottom slope is small. From these curves, determine the critical depth for each discharge. %3D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Figure: 1** **b)** Plot the specific energy versus depth curves (on normal graph paper) for Q = 400 and 800 m³/s in a trapezoidal channel with a bottom width of 20m and side slopes of 2H:1V. Assume the bottom slope is small. From these curves, determine the critical depth for each discharge. For the educational purpose of this exercise, students should use the following steps: 1. **Graph Setup:** - Use normal graph paper with depth on the x-axis and specific energy on the y-axis. - Determine the range for each axis based on channel dimensions and expected flow characteristics. 2. **Channel Characteristics:** - Bottom width = 20m. - Side slopes = 2H:1V, meaning for every 2m horizontally, the channel rises 1m vertically. 3. **Discharge Values:** - Q = 400 m³/s. - Q = 800 m³/s. 4. **Plotting Curves:** - Calculate specific energy for various depths at the given discharges. - Plot the specific energy versus depth points and draw smooth curves for the different discharge rates. 5. **Critical Depth Determination:** - Identify the point on the curve where the specific energy is minimized for each discharge rate. This point represents the critical depth. Understanding how to plot these curves and determine critical depth is essential for analyzing flow characteristics in open channel hydraulics.
Transcribed Image Text:**Figure: 1** **b)** Plot the specific energy versus depth curves (on normal graph paper) for Q = 400 and 800 m³/s in a trapezoidal channel with a bottom width of 20m and side slopes of 2H:1V. Assume the bottom slope is small. From these curves, determine the critical depth for each discharge. For the educational purpose of this exercise, students should use the following steps: 1. **Graph Setup:** - Use normal graph paper with depth on the x-axis and specific energy on the y-axis. - Determine the range for each axis based on channel dimensions and expected flow characteristics. 2. **Channel Characteristics:** - Bottom width = 20m. - Side slopes = 2H:1V, meaning for every 2m horizontally, the channel rises 1m vertically. 3. **Discharge Values:** - Q = 400 m³/s. - Q = 800 m³/s. 4. **Plotting Curves:** - Calculate specific energy for various depths at the given discharges. - Plot the specific energy versus depth points and draw smooth curves for the different discharge rates. 5. **Critical Depth Determination:** - Identify the point on the curve where the specific energy is minimized for each discharge rate. This point represents the critical depth. Understanding how to plot these curves and determine critical depth is essential for analyzing flow characteristics in open channel hydraulics.
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