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A 2400 kg elevator accelerates upward at 1.40 m/s² for 15.0 m , starting from rest.

A 2400 kg elevator accelerates upward at 1.40 m/s² for 15.0 m , starting from rest.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Part D, please. Thank you!

**Elevator Physics Problem** A 2400 kg elevator accelerates upward at \(1.40 \, \text{m/s}^2\) for \(15.0 \, \text{m}\), starting from rest. ### Part A Calculate the work done by gravitational force on the elevator. - **Answer:** \(-3.53 \times 10^5 \, \text{J}** ### Part B How much work does the tension in the elevator cable do on the elevator? - **Answer:** \(4.03 \times 10^5 \, \text{J}\) ### Part C Use the work-kinetic energy theorem to find the kinetic energy of the elevator as it reaches \(15.0 \, \text{m}\). - **Answer:** \(5.04 \times 10^4 \, \text{J}\) ### Part D What is the speed of the elevator as it reaches \(15.0 \, \text{m}\)? - **Input Attempt:** \(16500 \, \text{m/s}\) - **Feedback:** Incorrect; enter your answer using units of velocity. Ensure calculations for velocity align with physical expectations and proper units.
Transcribed Image Text:**Elevator Physics Problem** A 2400 kg elevator accelerates upward at \(1.40 \, \text{m/s}^2\) for \(15.0 \, \text{m}\), starting from rest. ### Part A Calculate the work done by gravitational force on the elevator. - **Answer:** \(-3.53 \times 10^5 \, \text{J}** ### Part B How much work does the tension in the elevator cable do on the elevator? - **Answer:** \(4.03 \times 10^5 \, \text{J}\) ### Part C Use the work-kinetic energy theorem to find the kinetic energy of the elevator as it reaches \(15.0 \, \text{m}\). - **Answer:** \(5.04 \times 10^4 \, \text{J}\) ### Part D What is the speed of the elevator as it reaches \(15.0 \, \text{m}\)? - **Input Attempt:** \(16500 \, \text{m/s}\) - **Feedback:** Incorrect; enter your answer using units of velocity. Ensure calculations for velocity align with physical expectations and proper units.
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