A 65 kg student stands on a bathroom scale in an elevator. She notices that the scale reads 520 N. Assume downward is positive. Round all answers to the whole numbers. 1. The scale reads the actual (actual/apparent) weight of the student. 2. There are 2 forces in the FBD. 3. The student's weight is 637 N. 4. The net force acting on the student is N. 5. The acceleration of the elevator is m/s?. 6. If the elevator has a speed of 1.7 m/s, it travels m after 3 s.

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### Problem Description:

A 65 kg student stands on a bathroom scale in an elevator. She notices that the scale reads 520 N. Assume downward is positive. Round all answers to whole numbers.

1. **The scale reads the** ___actual___ **(actual/apparent) weight of the student.**

2. **There are** ___2___ **forces in the FBD.**

3. **The student’s weight is** ___637___ **N.**

4. **The net force acting on the student is** _______ **N.**

5. **The acceleration of the elevator is** _______ **m/s².**

6. **If the elevator has a speed of 1.7 m/s, it travels** _______ **m after 3 s.**

### Explanation:

- **Weight Calculation:** 
  - The weight of the student is given as 637 N, calculated using \( W = mg \), where \( m = 65 \) kg and \( g = 9.8 \) m/s².

- **Forces in the Free Body Diagram (FBD):** 
  - Two forces are acting on the student: gravity (weight) and the normal force exerted by the scale.

### Tasks:

- **Net Force:** 
  - The net force can be calculated using \( F_{\text{net}} = F_{\text{scale}} - F_{\text{gravity}} \).

- **Acceleration:** 
  - The acceleration of the elevator can be derived from \( F_{\text{net}} = ma \).

- **Distance Traveled:**
  - Using the formula for distance, \( d = vt + \frac{1}{2}at^2 \), find the distance traveled by the elevator.
Transcribed Image Text:### Problem Description: A 65 kg student stands on a bathroom scale in an elevator. She notices that the scale reads 520 N. Assume downward is positive. Round all answers to whole numbers. 1. **The scale reads the** ___actual___ **(actual/apparent) weight of the student.** 2. **There are** ___2___ **forces in the FBD.** 3. **The student’s weight is** ___637___ **N.** 4. **The net force acting on the student is** _______ **N.** 5. **The acceleration of the elevator is** _______ **m/s².** 6. **If the elevator has a speed of 1.7 m/s, it travels** _______ **m after 3 s.** ### Explanation: - **Weight Calculation:** - The weight of the student is given as 637 N, calculated using \( W = mg \), where \( m = 65 \) kg and \( g = 9.8 \) m/s². - **Forces in the Free Body Diagram (FBD):** - Two forces are acting on the student: gravity (weight) and the normal force exerted by the scale. ### Tasks: - **Net Force:** - The net force can be calculated using \( F_{\text{net}} = F_{\text{scale}} - F_{\text{gravity}} \). - **Acceleration:** - The acceleration of the elevator can be derived from \( F_{\text{net}} = ma \). - **Distance Traveled:** - Using the formula for distance, \( d = vt + \frac{1}{2}at^2 \), find the distance traveled by the elevator.
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