A 20mm thick plate Fy = 250 Mpa, Fu = 415 Mpa, has 20mm nominal bolt holes. Using ASD and LRFD (NSCP 2015), the following apply. For tensile yiielding on gross section : Pn = Fy Ag, reduction factor = 0.90 (LRFD), factor of safety = 1.67 (ASD). For tensile rupture in net area section : Pn = Fu Ae , reduction factor = 0.75 (LRFD), factor of safety = 2.00 (ASD). Determine the tension iin yielding capacity and tension rupture capacity of the connection. 75 37.5 375 50 50 50 50 37.5 37.5 37.5
A 20mm thick plate Fy = 250 Mpa, Fu = 415 Mpa, has 20mm nominal bolt holes. Using ASD and LRFD (NSCP 2015), the following apply. For tensile yiielding on gross section : Pn = Fy Ag, reduction factor = 0.90 (LRFD), factor of safety = 1.67 (ASD). For tensile rupture in net area section : Pn = Fu Ae , reduction factor = 0.75 (LRFD), factor of safety = 2.00 (ASD). Determine the tension iin yielding capacity and tension rupture capacity of the connection. 75 37.5 375 50 50 50 50 37.5 37.5 37.5
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![A 20mm thick plate Fy = 250 Mpa, Fu = 415 Mpa, has 20mm nominal bolt holes. Using ASD and LRFD (NSCP
2015), the following apply. For tensile yiielding on gross section : Pn = Fy Ag, reduction factor = 0.90 (LRFD), factor
of safety = 1.67 (ASD). For tensile rupture
of safety = 2.00 (ASD). Determine the tension iin yielding capacity and tension rupture capacity of the connection.
net area section : Pn = Fu Ae , reduction factor = 0.75 (LRFD) , factor
50
37.5
375
75
50
50
50
50
37.5 375 375
37.5 37.5 37.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23d93f67-ca0e-4e78-bcc4-ce7e4f314052%2Fa277a84a-52b7-4aa2-90a6-d700d198abb2%2Fit2zgxl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 20mm thick plate Fy = 250 Mpa, Fu = 415 Mpa, has 20mm nominal bolt holes. Using ASD and LRFD (NSCP
2015), the following apply. For tensile yiielding on gross section : Pn = Fy Ag, reduction factor = 0.90 (LRFD), factor
of safety = 1.67 (ASD). For tensile rupture
of safety = 2.00 (ASD). Determine the tension iin yielding capacity and tension rupture capacity of the connection.
net area section : Pn = Fu Ae , reduction factor = 0.75 (LRFD) , factor
50
37.5
375
75
50
50
50
50
37.5 375 375
37.5 37.5 37.5
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