A 200-N/C electric field is in the positive x direction. The force on an electron in this field is: 200 N in the positive x direction 200 N in the negative x direction 3.2 x 10-17 N, in the positive x direction 3.2 x 10-17 N, in the negative x direction ΟΝ

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### Understanding the Force on an Electron in an Electric Field

In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula:

\[ F = qE \]

Here:
- \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C)
- \( E \) is the electric field strength, given as 200 N/C 

Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force:

### Calculation Details
\[ F = qE \]
\[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \]
\[ F ≈ -3.2 \times 10^{-17} \, \text{N} \]

Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron.

### Answer Choices
The question and answers are presented as a multiple-choice format:

- ☐ 200 N in the positive x direction
- ☐ 200 N in the negative x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
- ☐ 0 N

The correct choice, given the above calculation, is:
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
Transcribed Image Text:### Understanding the Force on an Electron in an Electric Field In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula: \[ F = qE \] Here: - \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C) - \( E \) is the electric field strength, given as 200 N/C Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force: ### Calculation Details \[ F = qE \] \[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \] \[ F ≈ -3.2 \times 10^{-17} \, \text{N} \] Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron. ### Answer Choices The question and answers are presented as a multiple-choice format: - ☐ 200 N in the positive x direction - ☐ 200 N in the negative x direction - ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction - ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction - ☐ 0 N The correct choice, given the above calculation, is: - ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
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