A 200-N/C electric field is in the positive x direction. The force on an electron in this field is: 200 N in the positive x direction 200 N in the negative x direction 3.2 x 10-17 N, in the positive x direction 3.2 x 10-17 N, in the negative x direction ΟΝ
A 200-N/C electric field is in the positive x direction. The force on an electron in this field is: 200 N in the positive x direction 200 N in the negative x direction 3.2 x 10-17 N, in the positive x direction 3.2 x 10-17 N, in the negative x direction ΟΝ
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Understanding the Force on an Electron in an Electric Field
In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula:
\[ F = qE \]
Here:
- \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C)
- \( E \) is the electric field strength, given as 200 N/C
Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force:
### Calculation Details
\[ F = qE \]
\[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \]
\[ F ≈ -3.2 \times 10^{-17} \, \text{N} \]
Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron.
### Answer Choices
The question and answers are presented as a multiple-choice format:
- ☐ 200 N in the positive x direction
- ☐ 200 N in the negative x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
- ☐ 0 N
The correct choice, given the above calculation, is:
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67028db1-3c15-42d7-aa43-8659f6c3f0f2%2F7ee57ec8-b727-402f-b3e5-e83f350ee25c%2F5y7yprh_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding the Force on an Electron in an Electric Field
In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula:
\[ F = qE \]
Here:
- \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C)
- \( E \) is the electric field strength, given as 200 N/C
Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force:
### Calculation Details
\[ F = qE \]
\[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \]
\[ F ≈ -3.2 \times 10^{-17} \, \text{N} \]
Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron.
### Answer Choices
The question and answers are presented as a multiple-choice format:
- ☐ 200 N in the positive x direction
- ☐ 200 N in the negative x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
- ☐ 0 N
The correct choice, given the above calculation, is:
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
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