A 200-N/C electric field is in the positive x direction. The force on an electron in this field is: 200 N in the positive x direction 200 N in the negative x direction 3.2 x 10-17 N, in the positive x direction 3.2 x 10-17 N, in the negative x direction ΟΝ
A 200-N/C electric field is in the positive x direction. The force on an electron in this field is: 200 N in the positive x direction 200 N in the negative x direction 3.2 x 10-17 N, in the positive x direction 3.2 x 10-17 N, in the negative x direction ΟΝ
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![### Understanding the Force on an Electron in an Electric Field
In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula:
\[ F = qE \]
Here:
- \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C)
- \( E \) is the electric field strength, given as 200 N/C
Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force:
### Calculation Details
\[ F = qE \]
\[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \]
\[ F ≈ -3.2 \times 10^{-17} \, \text{N} \]
Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron.
### Answer Choices
The question and answers are presented as a multiple-choice format:
- ☐ 200 N in the positive x direction
- ☐ 200 N in the negative x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
- ☐ 0 N
The correct choice, given the above calculation, is:
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67028db1-3c15-42d7-aa43-8659f6c3f0f2%2F7ee57ec8-b727-402f-b3e5-e83f350ee25c%2F5y7yprh_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding the Force on an Electron in an Electric Field
In the scenario provided, a 200-N/C electric field (E) is oriented in the positive x direction. To determine the force (F) acting on an electron within this electric field, we can use the formula:
\[ F = qE \]
Here:
- \( q \) is the charge of the electron, which is approximately \(-1.6 \times 10^{-19} \) Coulombs (C)
- \( E \) is the electric field strength, given as 200 N/C
Since the electron has a negative charge, the direction of the force will be opposite to the direction of the electric field. Let's calculate the force:
### Calculation Details
\[ F = qE \]
\[ F = (-1.6 \times 10^{-19} \, \text{C}) \times (200 \, \text{N/C}) \]
\[ F ≈ -3.2 \times 10^{-17} \, \text{N} \]
Therefore, the force on the electron in this electric field is approximately \(3.2 \times 10^{-17}\) N in the negative x direction due to the negative charge of the electron.
### Answer Choices
The question and answers are presented as a multiple-choice format:
- ☐ 200 N in the positive x direction
- ☐ 200 N in the negative x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the positive x direction
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
- ☐ 0 N
The correct choice, given the above calculation, is:
- ☐ 3.2 × 10⁻¹⁷ N, in the negative x direction
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
![Physics for Scientists and Engineers](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
![Lecture- Tutorials for Introductory Astronomy](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
![College Physics: A Strategic Approach (4th Editio…](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON