A 20-tablet sample of soluble saccharin was treated with 20.00 ml of 0.08181 M AgNO3. The reaction is : R-N-Na + Ag*= R-N-Ag(s) + Na* After removal of the solid, titration of the filtrate and washings required 2.81 ml of 0.04124 M SCN". Ag* + SCN- S AgSCN(s) Ag+ titrated with SCN- represents the unreacted Ag* in the bove solution.) Calculate the average number of milligrams of saccharin (205.17) in each tablet.

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A 20-tablet sample of soluble saccharin was treated with 20.00 mL of 0.08181 M AgNO3 . The reaction is : • R-N-Na + Ag+  R-N-Ag(s) + Na+ • After removal of the solid, titration of the filtrate and washings required 2.81 mL of 0.04124 M SCN- . Ag+ + SCN−  AgSCN(s) (Ag+ titrated with SCNrepresents the unreacted Ag+ in the above solution.) • Calculate the average number of milligrams of saccharin (205.17) in each tablet.

Exercise
A 20-tablet sample of soluble saccharin was treated with
20.00 mL of 0.08181 M AGNO3. The reaction is :
R-N-Na + Ag* = R-N-Ags) + Na*
After removal of the solid, titration of the filtrate and
washings required 2.81 ml of 0.04124 M SCN-.
Ag+ + SCN- S AgSCN(s)
(Ag* titrated with SCN represents the unreacted Ag* in the
above solution.)
Calculate the average number of milligrams of saccharin
(205.17) in each tablet.
Transcribed Image Text:Exercise A 20-tablet sample of soluble saccharin was treated with 20.00 mL of 0.08181 M AGNO3. The reaction is : R-N-Na + Ag* = R-N-Ags) + Na* After removal of the solid, titration of the filtrate and washings required 2.81 ml of 0.04124 M SCN-. Ag+ + SCN- S AgSCN(s) (Ag* titrated with SCN represents the unreacted Ag* in the above solution.) Calculate the average number of milligrams of saccharin (205.17) in each tablet.
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