A 2.90-kg object is moving in a plane, with its x and y coordinates given by x = 2t - 4 and y = 4t + 3, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting or this object at t = 2.25 s. 139.68 If you know the position of an object as a function of time, you can calculate the acceleration as a function of time using calculus methods. N

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2t?
4 and y = 4t + 3, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on
A 2.90-kg object is moving in a plane, with its x and y coordinates given by x =
this object att = 2.25 s.
-
139.68
If you know the position of an object as a function of time, you can calculate the acceleration as a function of time using calculus methods. N
Transcribed Image Text:2t? 4 and y = 4t + 3, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on A 2.90-kg object is moving in a plane, with its x and y coordinates given by x = this object att = 2.25 s. - 139.68 If you know the position of an object as a function of time, you can calculate the acceleration as a function of time using calculus methods. N
A 14.0 g bullet is moving to the right with speed 300 m/s when it hits a target and travels an additional 21.0 cm into the target. What are the magnitude (in N) and direction of the stopping force
acting on the bullet? Assume the stopping force is constant.
magnitude
1575
Apply the time-independent kinematic equation to the bullet while it travels in the target, with v, = 0. Solve for the acceleration, and use this value in Newton's second law to determine
f, the stopping force on the bullet. Be sure to convert units as necessary. N
direction
to the left
Transcribed Image Text:A 14.0 g bullet is moving to the right with speed 300 m/s when it hits a target and travels an additional 21.0 cm into the target. What are the magnitude (in N) and direction of the stopping force acting on the bullet? Assume the stopping force is constant. magnitude 1575 Apply the time-independent kinematic equation to the bullet while it travels in the target, with v, = 0. Solve for the acceleration, and use this value in Newton's second law to determine f, the stopping force on the bullet. Be sure to convert units as necessary. N direction to the left
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