Answered: A 2.00 kg box is suspended from the end… | bartleby

Related questions

Question

A 2.00 kg box is suspended from the end of a
light vertical rope. A time-dependent force is applied to the upper
end of the rope, and the box moves upward with a velocity magnitude
that varies in time according to v1t2 = (2.00 m/s2)t +(0.600 m/s3)t2.
What is the tension in the rope when the velocity of the box is
9.00 m/s?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

While pushing your 55.0 kg lawnmower across the lawn (μ = 0.100) you notice that the handle makes an angle that is 55.0° below the horizontal. What force must you push the lawnmower with in order to have it accelerate at 2.0 m/s²?
4.3 kg A 4.3 kg object hangs at one end of a rope that is attached to a support on a railroad boxcar. When the car accelerates to the right, the rope makes an angle of 37° with the vertical. The acceleration of gravity is 9.8 m/s² . Find the acceleration of the car. Answer in units of m/s². (
A student attaches a rope to a 32 kg box, and drags it to the left with constant velocity of 1.97 m/s. The tension in the rope is 207 N at an angle of 35.7° to the ground. How much does the box weigh? Find the x and y components of the applied (tension) force: Fx = N. %3D Fy = N. How much friction must be present? How much Normal force must be present? N.
A man stands on a scale in an elevator that is accelerating upward. The scale reads 973.8 N. When he holds a 44.0 kg box, the scale reads 1449.8 N. What is the man's mass? and What is the magnitude of the acceleration of the elevator?
Sphere A is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here m₁ = m₂ = m = 3.67 kg. = = T₁ m₁ (a) The elevator starts from rest and accelerates downward with a = 1.35 m/s². What are the tensions in the two strings in newtons? T₁ N N T2 = T₂ m₂ (b) If the elevator moves upward instead with the same acceleration what will be the tension in the two strings in newtons? Т1 T2 N N (c) The maximum tension the two strings can withstand is 89.8 N. What maximum upward acceleration (in m/s2) can the elevator have without having one of the strings break? m/s²
A 3.00 kg box is suspended from the end of a light vertical rope. A time-dependent force is applied to the upper end of the rope, and the box moves upward with a velocity magnitude that varies in time according to v(t) = (2.00m/s²)t + (0.600m/s³)t² ▼ Part A What is the tension in the rope when the velocity of the box is 9.00 m/s? Express your answer with the appropriate units. T= O μA Value Submit Request Answer Units ? Review | Cons
A 34.8 kg child is sitting at the top of a slide, which is inclined at an angle of 55 degrees with respect to the horizontal. Someone gives the child a quick push to get them moving, after which they slide down the incline without any further assistance. The coefficient of kinetic friction between the child and the slide is μ s = 0.44. What is the magnitude of the acceleration (in m/s2) of the child?
A student attaches a rope to a 32 kg box, and drags it to the left with constant velocity of 1.08 m/s. The tension in the rope is 235 N at an angle of 48.7° to the ground. How much does the box weigh? 313.92 Find the x and y components of the applied (tension) force: Fx = 155.10 V o N %3D Fy = 176.5 N. %3D How much friction must be present? 155.10 V oN How much Normal force must be present? N. Submit Question
A crate of mass 38.6 kg rests on a level surface, with a coefficient of kinetic friction 0.258. You push on the crate with an applied force of 219 N. What is the magnitude of the crate s acceleration as it slides? A 6.80 m/s^2 B 3.14 m/s^2 C 5.67 m/s^2 D 2.51 m/s^2
A contestant in a winter sports contest pulls a 47 kg brick of ice 25 degrees in the positive horizontal direction with a rope over his shoulders over a frozen lake. Assume the coefficients of static and kinetic friction are µs=0.1 and µk=0.03. 1. Calculate the minimum force F he must exert to get the brick sliding in newtons. 2. What is its acceleration in m/s2 once it starts to move, if that force is maintained?