Problem 5: An elevator brimming with passengers has a mass of 1500 kg.art (a) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.5 m/s² for 2.5 s. Calculate the tension in the cable supportingthe elevator in newtons.T-1.695 x 10¹T-1470 x 10✔Correct!The elevator continues upward at constant velocity for 8.6 s. What is the tension in the cable, in newtons, during this time?✔Correct!The elevator experiences a negative acceleration at a rate of 0.65 m/s² for 2.7 s. What is the tension in the cable, in newtons, during this period ofnegative acceleration?T-137257-1.373x10 ✔Correct!Part (d) How far, in meters, has the elevator moved above its original starting point?y 13725

We will use Newton's second law to find the tension in the cable. We then use kinematic equation of…

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