Problem 5: An elevator brimming with passengers has a mass of 1500 kg. t(a) The elevato accelerates upward (in the positive direction) from rest at a rate of 1.5 m/s² for 2.5 s. Calculate the tension in the cable supporting the elevator in newtons T-1.695 × 10 7-1470 x 10 ✔Correct! b) The elevator continues upward at constant velocity for 8.6s. What is the tension in the cabl ✔Correct! The elevator experiences a negative acceleration at a rate of 0.65 ms for 2.7s. What is the tension in the cable, in newtons, during this period of negative acceleration? T-13725 7-1.373 x 10² ✔Cornet! Part (d) How far, in meters, has the elevator moved above its original starting point? y-13725 newtons, during this time?
Problem 5: An elevator brimming with passengers has a mass of 1500 kg. t(a) The elevato accelerates upward (in the positive direction) from rest at a rate of 1.5 m/s² for 2.5 s. Calculate the tension in the cable supporting the elevator in newtons T-1.695 × 10 7-1470 x 10 ✔Correct! b) The elevator continues upward at constant velocity for 8.6s. What is the tension in the cabl ✔Correct! The elevator experiences a negative acceleration at a rate of 0.65 ms for 2.7s. What is the tension in the cable, in newtons, during this period of negative acceleration? T-13725 7-1.373 x 10² ✔Cornet! Part (d) How far, in meters, has the elevator moved above its original starting point? y-13725 newtons, during this time?
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Transcribed Image Text:Problem 5: An elevator brimming with passengers has a mass of 1500 kg.
art (a) The elevator accelerates upward (in the positive direction) from rest at a rate of 1.5 m/s² for 2.5 s. Calculate the tension in the cable supporting
the elevator in newtons.
T-1.695 x 10¹
T-1470 x 10
✔Correct!
The elevator continues upward at constant velocity for 8.6 s. What is the tension in the cable, in newtons, during this time?
✔Correct!
The elevator experiences a negative acceleration at a rate of 0.65 m/s² for 2.7 s. What is the tension in the cable, in newtons, during this period of
negative acceleration?
T-13725
7-1.373x10 ✔Correct!
Part (d) How far, in meters, has the elevator moved above its original starting point?
y 13725
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VIEWStep 2: Write expression for Newton's second law
VIEWStep 3: Find tension in the cable when elevator has positive acceleration
VIEWStep 4: Find tension in cable when elevator moves at constant speed
VIEWStep 5: Find tension in cable when elevator has negative acceleration
VIEWStep 6: Find distance travelled by the elevator
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