A 2.0 kg wood box is help stationary against a vertical wood wall while you push upward on it at a 45° angle. For wood on wood, the coefficient of kinetic friction is μ = 0.20 and Hk H₂=0.30. Find (1) Fmin the minimum push force needed to stop the box from sliding along with (2) Fmax the maximum force that can be applied before the box slides. Also find (3) the frictional force vector when F. (F + F min)/2. push max -
A 2.0 kg wood box is help stationary against a vertical wood wall while you push upward on it at a 45° angle. For wood on wood, the coefficient of kinetic friction is μ = 0.20 and Hk H₂=0.30. Find (1) Fmin the minimum push force needed to stop the box from sliding along with (2) Fmax the maximum force that can be applied before the box slides. Also find (3) the frictional force vector when F. (F + F min)/2. push max -
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Transcribed Image Text:A 2.0 kg wood box is help stationary against a vertical wood
wall while you push upward on it at a 45° angle. For wood
on wood, the coefficient of kinetic friction is µ = 0.20 and
P₁ = 0.30.
Find (1) Fmin the minimum push force needed to stop the
box from sliding along with (2) Fmax the maximum force
that can be applied before the box slides. Also find (3) the
frictional force vector when F
(Fmax + Fmin)/2.
push
H
Transcribed Image Text:2.0 kg
45°
F
push
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This question can be done using friction force and equillibrium
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