**Problem Statement:**A block of mass 1.33 kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3 N, what is the static friction coefficient?**Explanation:**This scenario involves understanding the concept of static friction between the block and the surface it is on. The static friction coefficient (\(\mu_s\)) can be determined using the formula:\[ F_{\text{static}} = \mu_s \times N \]Where:- \( F_{\text{static}} \) is the maximum static frictional force (14.3 N in this case).- \( \mu_s \) is the static friction coefficient.- \( N \) is the normal force (equal to the gravitational force on the block, i.e., mass \(\times\) gravity, \(1.33 \, \text{kg} \times 9.8 \, \text{m/s}^2\)).The calculation involves balancing forces to find \(\mu_s\).

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A block of mass 1.33kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3N, what is the static friction coefficient?

A block of mass 1.33kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3N, what is the static friction coefficient?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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**Problem Statement:**

A block of mass 1.33 kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3 N, what is the static friction coefficient?

**Explanation:**

This scenario involves understanding the concept of static friction between the block and the surface it is on. The static friction coefficient (\(\mu_s\)) can be determined using the formula:

\[ F_{\text{static}} = \mu_s \times N \]

Where:
- \( F_{\text{static}} \) is the maximum static frictional force (14.3 N in this case).
- \( \mu_s \) is the static friction coefficient.
- \( N \) is the normal force (equal to the gravitational force on the block, i.e., mass \(\times\) gravity, \(1.33 \, \text{kg} \times 9.8 \, \text{m/s}^2\)).

The calculation involves balancing forces to find \(\mu_s\).

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