A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate. 48.30 mass: g Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration. 3.576 [Na*] =| M Incorrect 2.763 [NO,] = M Incorrect 0.739 [Sr*] = M Incorrect 1.788 [F=] = M Incorrect
A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate. 48.30 mass: g Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration. 3.576 [Na*] =| M Incorrect 2.763 [NO,] = M Incorrect 0.739 [Sr*] = M Incorrect 1.788 [F=] = M Incorrect
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the
< Feedback
mass of the resulting strontium fluoride precipitate.
The sodium ion concentration you
calculated is incorrect.
When calculating the Na+
concentration, you may have used the
48.30
mass:
volume of the original NaF solution.
Instead, use the total volume of both
Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for
solutions to calculate the concentration
the concentration.
in the final solution.
3.576
[Na*] =
M
Incorrect
2.763
[NO,] =
M
Incorrect
0.739
[Sr**] =
M
Incorrect
1.788
[F=] =
M
Incorrect](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4cbada35-3122-4a6c-a25c-246bca0ae236%2F74d42509-6a39-4c94-bfeb-599449db7f5b%2Fsb6mzks_processed.png&w=3840&q=75)
Transcribed Image Text:A 190.0 mL solution of 2.765 M strontium nitrate is mixed with 215.0 mL of a 3.581 M sodium fluoride solution. Calculate the
< Feedback
mass of the resulting strontium fluoride precipitate.
The sodium ion concentration you
calculated is incorrect.
When calculating the Na+
concentration, you may have used the
48.30
mass:
volume of the original NaF solution.
Instead, use the total volume of both
Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for
solutions to calculate the concentration
the concentration.
in the final solution.
3.576
[Na*] =
M
Incorrect
2.763
[NO,] =
M
Incorrect
0.739
[Sr**] =
M
Incorrect
1.788
[F=] =
M
Incorrect
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