A 16-ft- (4.8-m-) span simply supported beam, as shown in the figure below, has a clear span of 15 ft (4.5 m) and is supported by 12 x 12-in. (300 × 300-mm) columns. The beam carries a factored uniform load of 11.1K/ft (166 kN/m). The dimensions of the beam section and the flexural steel reinforcement are shown in figure. Design the necessary shear reinforcements using f'c = 3 ksi (21MPa) and fyt =60 ksi(420MPa). Show the

A 16-ft- (4.8-m-) span simply supported beam, as shown in the figure below, has a clear span of 15 ft (4.5 m) and is supported by 12 x 12-in. (300 × 300-mm) columns. The beam carries a factored uniform load of 11.1K/ft (166 kN/m). The dimensions of the beam section and the flexural steel reinforcement are shown in figure. Design the necessary shear reinforcements using f'c = 3 ksi (21MPa) and fyt =60 ksi(420MPa). Show the

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A reinforced concrete T- beam, section in Figure 2 (a), is subjected to an ultimate uniformload and concentrated loads as shown in the Figure 2(b). The beam is reinforced with 6-28 mm diameter tension bars at the point of maximum positive moment (at midspan -bars at the bottom), and 3-28 mm diameter tension bars at the point of maximum negativemoment (at the supports - bars at the top) .. The design properties used are: f ‘c = 21MPa and fy = 414 MPa, ; flange width = 650 mm, flange thickness is = 90 mm; webthickness = 250 mm; effective depth = 410 mm. Need to answer Q. Determine the safe value of Pu as required by flexure at the point of maximumpositive moment
A beam is simply supported and has a span of 12 m. The beam is a W33×240 with Ey=345 MPa. Compute the allowable (ASD) and ultimate (LRFD) uniformly distributed load that can be safely carried by the beam including its weight: A. If the length of the beam is 14m and the compression flange has lateral supports only at its ends and the midspan. Express your answer in N/m. (ASD) B. If the length of the beam is 14m and the compression flange has lateral supports only at its ends and the midspan. Express your answer in kN/m. (LRFD)| (Ctrl) Properties of W33×240: Weight = 3.51 kN/m tw = 21.08 mm x = 352.54 mm A = 45,548 mm? Ix = 5,660.75 × 10® mmª ry = 92.34 mm d = 850.9 mm ly = 388.34 × 10® mm Jc = 14.51 x 106 mm* bị = 402.97 mm Sx = 13,322.68 × 10° mm3 ris = 105.92 mm %3D t = 35.56 mm Sy = 1,933.67 x 10° mm3 %3D
View Policies Current Attempt in Progress The wood beam supports loads of w = 460 lb/ft and P = 120O Ib on span lengths of LAB = 9.0 ft, LBC = 4.5 ft, and LcD= 4.5 ft. The beam cross section has dimensions of b, = 1.4 in., d, = 4.2 in., b2 = 4.5 in., and d, = 11.60 in. Determine the magnitude and location of: (a) the maximum horizontal shear stress in the beam. (b) the maximum tensile bending stress in the beam. P W di d2 B LAB LBC LCD by b2 Answer: (а) Тmax psi (b) Omax = psi Save for Later Attempts: 0 of 1 used Submit Answer
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Q1/ Calculate (b, d, h and As) for the cantilever beam shown below if the applied point load (Pa 78.5 kN and PL=100 kN) and fe = 35 MPa and f 400 MPa: P. Pa 3.5 m I m
Please answer the problem attached image. Using NSCP 2015 thank you very much.
Problem Statement- Given the Simply-Supported Beam shown below with: - Service DL = 24 kN/m including the self-weight of the beam & Service LL = 16 kN/m Span of the beam is 7.5 m to the center of the columns (columns are 0.5 m x 0.5 m) Top, bottom, and side covers to center of steel = 50 mm The beam cross-section is rectangular with b = 350 mm & total depth h = 550 mm Reinforcement is 5 ¢ 25 at the maximum moment location Compression steel 2 o 19 (top cover = 50 mm) Use f'= 21 MPa & = 420 MPa SLL = 16 KNm SDL = 24 KN/m 7.5 m (1) Check if the flexural Strength is adequate: analyze as doubly-reinforced beam be (2) Design the beam for shear and show you final design details neatly; use o10 stirrups ( (3) Calculate the required development length of the No. 25 bars (the bars are not epoxy-coated, normal weight concrete, take (Ctku da) = 2.0, & then check at what location from the beam centerline 3 of the 5 bars can be cut-off (4) Calculate Ie & and check if the floor beam meets the ACI…
A beam is simply supported and has a span of 12 m. The beam is a W33×240 with Ey=345 MPa. Compute the following: A. If the compression flange is fully braced laterally. Express your answer in kN/m. (ASD) B. If the compression flange is fully braced laterally. Express your answer in kN/m. (LRFD) Properties of W33×240: Weight = 3.51 kN/m tw = 21.08 mm x = 352.54 mm A = 45,548 mm? Ix = 5,660.75 × 10® mm ry = 92.34 mm d = 850.9 mm ly = 388.34 x 10® mm* Je = 14.51 x 10° mm bị = 402.97 mm Sx = 13,322.68 x 10° mm3 ris = 105.92 mm %3D t = 35.56 mm Sy = 1,933.67 x 10° mm3
For the following plan it is required to: 1- Design all beams for flexure and shear, where they have additional 30 kN/m distributed factored load 2- Design the columns. The concrete has a strength of 30 MPa, and the yield strength of the steel is 420 MPa. Show full calculations and neat sketches. All dimensions are in m. I 03 B2 0,3 7 B1 Wu=20 kN/m2 B1
A composite beam spans a distance of L= 12 ft and is fabricated by adhering two wooden boards (b= 2 in., d= 8 in. and E = 1,500 ksi) to the sides of a steel plate (t = 0.4 in., d = 8 in. and E= 30,000 ksi). 400 lb 400 Ib 200 lb/ft d -3 ft- 3 ft V (lb) -6ft 600 400 (ft) 12 -400 -600 1. For the given loading condition, determine the maximum normal stress M (lb-ft) in the steel plate. A) 3,850 psi +x (ft) B) 1,550 psi -300 C) 2,250 psi D) 4,200 psi -1200 - 1200 E) None of the Above 2. If the allowable normal stress of the steel is 9,000 psi and the 200 lb/ft distributed load remians constant, determine the largest acceptable concentrated load on each end. A) 1,600 lb B) 2,325 lb C) 935 lb D) 860 lb E) None of the Above
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