A 12.3 g sample of an alloy of Mg (35%) and Al (65%) produces H2 when added 25 ml of 1.21 M HCI. Calculate the total H2 formed from the reaction. Calculate the mass of the unreacted excess reactant(s).

Q: What mass of precipitate is formed when 100. mL of  0.350 M  NaCl reacts with  100. mL  of  0.175 M…

A: When an insoluble substance is present in the chemical solution it is called a precipitate.…

Q: What mass of Na3CrO4 is required to precipitate all of the silver ions from 20.0 mL of a 0.700 M…

A: 20.0 mL of a 0.700 M solution of AgNO3 and Na3CrO4.

Q: If 35.9 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: For CH3OH solution, Given mass = 35.9 g Molar mass = 32.04 g mol-1 Volume of solution = 500 mL…

Q: A sample of 7.90 g of Mg(OH)2 is added to 25.6 mL of 0.225 M HNO3. a.) Write the chemical equation…

A: (a) When magnesium hydroxide added with nitric acid, Following balanced Chemical Reaction occurs -…

Q: A sodium sulfate solution is added to a 25.0 mL sample of a solution containing Ba2+ ions until no…

A: The reaction taking place here can be described as, Na2SO4(aq) + Ba2+(aq)→BaSO4(s) + 2Na+(aq)

Q: A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of…

A: Calculation for number of moles of ammonium sulfate:

Q: 24 is required to precipitate all of the siiver lons from 10.0 mL of a 0.000 M Solution of AgNO3…

A: Reaction between Na2CrO4 and AgNO3 Na2CrO4+2AgNO3−>Ag2CrO4+2NaNO3 Given Volume of AgNO3=10ml…

Q: If 50.0 g of CH₂OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Given,the mass of CH3OH = 50.0 gmolar mass of CH3OH = 32.04 g/molvolume of the water ( solution ) =…

Q: If 39.6 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Given, amount of CH3OH =39.6 g and molar mass of  CH3OH =32.04 gmolvolume of flask i.e. solution…

Q: What mass of precipitate is formed when 100. mL of  0.350 M  NaCl reacts with  100. mL  of  0.175 M…

A: In this question, we have to find out the correct answer of given problem by the help of the…

Q: If 22.0 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Mass of CH3OH = 22.0 g  Molar Mass = 32.04 g/mol  Volume = 500.0 mL  = 0.5 L

Q: When 3.5 g of CaF2 (an insoluble salt, Ksp = 3.9 X 10-11) is added to water to make 200. mL of…

A: mole  = mass  /  molecular weight molecular weight of CaF2 = 78.07 g/mole concentration = mole  *…

Q: A solution is prepared by mixing 25.0 mL of a 0.150 M potassium chloride (KCl) with 75.0 mL of a…

A: In this question we have to tell the molarity of K+ ions in the solution.

Q: When solution A and B are mixed together determine the mass of solid (in grams) produced by the…

A:

Q: The concentration of copper(II) sulfate in one brand of soluble plant fertilizer is 0.0700% by…

A:

Q: You have 18.46 mL of a .2987 M NaOH solution was used to titrate a KHP sample.  How many grams of…

A:

Q: If 26.5 g of CH3OH(MM=32.04g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A:

Q: Calculate the mass (g) of MgCO3 precipitated by mixing 10.00 mL of a 0.200 M Na2CO3 solution with…

A: The chemical reaction between Na2CO3 and Mg(NO3)2 is shown below.

Q: 3. A 12.3 g sample of an alloy of Mg (35%) and Al (65%) produces H2 when added to 25 ml of 1.21 M…

A: It is an example of stoichiometry where we need to establish a relation between the quantity of…

Q: A 5.0mL sample of a stock solution of concentrated HNO3, a strong acid, is diluted with distilled…

A: The ratio of moles of solute to the volume of solution in liters is known as molarity.

Q: If 23.9 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Molarity (M) is a concentration term for a solution. The molarity of the given solution is defined…

Q: A stock solution of Na2S2O3 is prepared by adding 20.40 grams of solid Na2S2O3 to enough water to…

A: Multiple questions

Q: The molar mass of potassium hydrogen phthalate (KHC8H4O4, abbreviation KHP) is 204.22 grams per…

A: Given data,Mass of KHP=1.32gMolar mass of KHP=204.22g/molVolume of NaOH=15.06mL=0.01506L

Q: A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of…

A: The question is based on the concept of molarity.    it is defined as number of moles of solute…

Q: What mass of solid product is formed when 50.0 mL of 0.10 M Pb(NO3)2 (aq) is mixed with 75.0 mL of…

A: The balanced Chemical equation takes place between aqueous lead Nitrate and aqueous sodium chloride…

Q: Barium can be analyzed by precipitating it as BaSO4 and determining the mass of the precipitate.…

A: Calculate the number of moles of BaSO4 formed:

Q: What mass of precipitate is formed when 100. mL of 0.350 M NaCl reacts with 100. mL of 0.175 M…

A: NaCl → Na+ + Cl- Pb(NO3)2 → Pb2+ +2NO3- Pb2+ →2Cl- → PbCl2 (precipitate)  Moles = Molarity * Volume…

Q: 18. A beverage mixture contains citric acid, C6H8O7 (molar mass 192 g/mol), plus sugar and…

A: Since 1 mole of citric acid will need only 1 mole of NaOH for complete neutralisation as it has only…

Q: the concentration of CH₃OH in the resulting solution?

A: Given,   Mass of CH3OH = 40.7 g Molar mass of CH3OH = 32.04 g/mol According to problem volume of…

Q: 3. A 2.315 g sample of H2C2O4•2H2O was transferred to a 100.0-mL volumetric flask and diluted to the…

A:

Q: Calculate the mass of MgCO3 precipitated by mixing 10.00 mL of a 0.200 M Na2CO3 solution with 5.00…

A: The following reaction is occurring: Determine the moles of Na2CO3 present in the reaction as shown…

Q: What mass of Na2CrO4 is required to precipitate all of the silver ions from 20.0 mL of a 0.700 M…

A: Molarity - ratio of number of moles of solute to the volume of solution in litres. Formula is,…

Q: 105 Chemistry I Laboratory Manual, 2017 Revision Questions: 1) What mass of KHP would you need in…

A: Chemical reaction between sodium hydroxide and KHP is given by:

Q: A 12.0 M solution of concentrated nitric acid has 25.0 mL withdrawn from it. The 25.0 mL sample is…

A: Consider the given information as follows; Initial concentration of nitric acid M1 = 12.0 M Initial…

Q: Calculate the mass of MgCO3 precipitated by mixing 10.00 mL of a 0.200 M Na2CO3 solution with 5.00…

A: Given: Volume of Na2CO3     = 10.00 mL Molarity of Na2CO3    = 0.200 M Volume of Mg(NO3)2  = 5.00 mL…

Q: A sodium sulfate solution is added to a 25.0 mL sample of a solution containing Ba2+ ions until no…

A: Given  mass of precipitate (BaSO4) = 1.21 g  Volume of the sample = 25 mL 233.37 g of BaSO4 comes…