A 100-turn coil is rotating with a constant angular speed in a uniform magnetic field of 0.486 T that is perpendicular to its surface at t = 0 s. The diameter of the coil is 10 cm. Calculate the magnitude (i.e., positive value) of the electric charge induced in the coil during half a revolution, in mC, if the resistance of the coil is 39.7 Ω.Calculate i like in the previous problem, and then solve the integral \( \int_{0}^{\frac{T}{2}} i \cdot dt \) to find the induced charge (T is the period).

Given, n=100 B= 0.486 T t=0s diameter of coil= 10 cm, r=5 cm=0.05 m R= 39.7 Ω

Answered: A 100-turn coil is rotating with a…

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