A 100 ml solution of 0.1 M glycine at pH 1.72 was titrated with 2 M LIOH. The pH was monitored and the result were plotted as shown in the graph. The key points of the titration are designated as I to V. Identify the key point in the titration corresponding to the pH at which the carboxyl group is half deprotonated. 12 J130 10 9.60 (IV) 8 pH 6-597 4 234 2. 05 1.0 1.5 2.0 OH (equivalents) IV O l and IV Next
A 100 ml solution of 0.1 M glycine at pH 1.72 was titrated with 2 M LIOH. The pH was monitored and the result were plotted as shown in the graph. The key points of the titration are designated as I to V. Identify the key point in the titration corresponding to the pH at which the carboxyl group is half deprotonated. 12 J130 10 9.60 (IV) 8 pH 6-597 4 234 2. 05 1.0 1.5 2.0 OH (equivalents) IV O l and IV Next
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:A 100 mL solution of 0.1 M glycine at pH 1.72 was titrated with 2 M LIOH. The pH was monitored and the result were plotted as shown in the graph. The key points of the titration are designated
as I to V. Identify the key point in the titration corresponding to the pH at which the carboxyl group is half deprotonated.
12
JL30
(V)
9.60
(IV)
8
5.97
pH 6
2.34
CII)
2
(I)
0.5
1.0
1.5
2.0
OH (equivalents)
IV
O Il and IV
Next
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