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A 1.9300 g impure sample of Fe(NH4)2(SO4)2 (FW = 392.14) was dissolved in 75 mL 0.75 M H2SO4 and was titrated with the standard KMnO4 in problem 1. Titration of the sample required 24.00mL while the blank containing only 75mL 0.75 M H2SO4 required 0.75 mL of the KMnO4 titrant. (Hint: subtract blank). Calculate the concentration of Fe(NH4)2(SO4)2 in %w/w in the impure sample. 5Fe²+ + MnO4 + 8H+ → 5Fe³+ + Mn²+ + 4H₂O

A 1.9300 g impure sample of Fe(NH4)2(SO4)2 (FW = 392.14) was dissolved in 75 mL 0.75 M H2SO4 and was titrated with the standard KMnO4 in problem 1. Titration of the sample required 24.00mL while the blank containing only 75mL 0.75 M H2SO4 required 0.75 mL of the KMnO4 titrant. (Hint: subtract blank). Calculate the concentration of Fe(NH4)2(SO4)2 in %w/w in the impure sample. 5Fe²+ + MnO4 + 8H+ → 5Fe³+ + Mn²+ + 4H₂O

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 1.9300 g impure sample of Fe(NH4)2(SO4)2 (FW = 392.14) was dissolved in 75 mL 0.75 M H2SO4 and was titrated with the standard KMnO4 in problem 1. Titration of the sample required 24.00mL while the blank containing only 75mL 0.75 M H2SO4 required 0.75 mL of the KMnO4 titrant. (Hint: subtract blank). Calculate the concentration of Fe(NH4)2(SO4)2 in %w/w in the impure sample. 5Fe²+ + MnO4 + 8H+ → 5Fe³+ + Mn²+ + 4H₂O 8.746% and 8.75% are incorrect
Transcribed Image Text:A 1.9300 g impure sample of Fe(NH4)2(SO4)2 (FW = 392.14) was dissolved in 75 mL 0.75 M H2SO4 and was titrated with the standard KMnO4 in problem 1. Titration of the sample required 24.00mL while the blank containing only 75mL 0.75 M H2SO4 required 0.75 mL of the KMnO4 titrant. (Hint: subtract blank). Calculate the concentration of Fe(NH4)2(SO4)2 in %w/w in the impure sample. 5Fe²+ + MnO4 + 8H+ → 5Fe³+ + Mn²+ + 4H₂O 8.746% and 8.75% are incorrect
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