A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axisVertical axial load = 256kNMy = 65kNmMx = 40kNmThe groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0. The Meyerhof bearing capacity factors are given below:What is the net allowable load (kN) of the footing?934.4591582.939None of the choices857.9331058.385847.372Please answer this asap. For upvote. Thank you very much $ (deg) N.NO (deg)N.N,5-141.000.0002622.2511.858.0025-381.090.0022723.9413.209-4635.632825.801.200.01014.7211.1903.5-901310.0232927.8616.4413.2364.6.191.430.0423030.1418.4015.6686.491.570.0703132.6720.6318.6686.6.811.720.10635-4923.183222.0227.161.880.1523338.6426.0926.1668.7-532.060.2093442.1629.4431.1456.7-922.250.2803546.1233-3037-152108.352.470.3673650.5937-7544426118.802.710.4713755,6342.9253-270129-282.970.5963861.3548.9364.073139.813-260.7443967.8755-967-3321410.373-590.9214075-3164.2093-6901510.983-941.1294183.8673-90113.9851611.634341.3754293-7185-38139-9851712.344771.66443105.1199.02171.1411813.105-262.00344118.37115.31211.4061913-935.802.40345133.88134.88262.73914.836.402.87146158.51328.72820152.102115.827.073-42147173.64187.21414-3222216.887.824,06648199.26222.31526.4442318.058.664,82449229-93265-51674-9082419-329.605-71650266.89319.07873.8432520.7210.666.765 Shape FactorsComponentFor o = 0For o > 10CohesionAa =1+0.2d =1+0.2tan 45 +Surchargedg = 1=1+0.1tan 45 +Unit WeightAyn = 1Ay = AgDepth FactorsComponentFor = 0°For o > 10°CohesionAed =1+0.2Aed =1+0.2tan 45+SurchargeAgd = 1Agr = 1+0.1tan 45 +BUnit WeightAyd = 1Ayd = AgdInclination FactorsComponentFormulaCohesiondi =90°Surcharge90B- width of the footingD, = depth of footingL- length of the footingUnit Weight

Answer we are given Square footing = 1.65 m * 1.65 m Cohesion c'= 134/2 =67 kpa Angle of friction…

Answered: A 1.65m wide square footing is embedded…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

A 1.65m wide square footing is embedded 1.81m beneath the ground surface. The soil about the ground water table has a unit weight of 16.79 kN/m3, saturated unit weight of 19.86 kN/m3, and an unconfined compressive strength of 134 kPa (hint: half of this is the cohesion). The angle of internal friction is 18 degrees.

The load acting on the column are given below. Assume a plan view where B is parallel to x-axis and L is parallel to the y-axis

Vertical axial load = 256kN
My = 65kNm
Mx = 40kNm
The groundwater table is 0.65m above the base of the footing. The factor of safety is 3.0.

The Meyerhof bearing capacity factors are given below:

What is the net allowable load (kN) of the footing?

934.459

1582.939

None of the choices

857.933

1058.385

847.372

Please answer this asap. For upvote. Thank you very much

$ (deg) N.
N
O (deg)
N.
N,
5-14
1.00
0.000
26
22.25
11.85
8.002
5-38
1.09
0.002
27
23.94
13.20
9-463
5.63
28
25.80
1.20
0.010
14.72
11.190
3.
5-90
131
0.023
29
27.86
16.44
13.236
4.
6.19
1.43
0.042
30
30.14
18.40
15.668
6.49
1.57
0.070
31
32.67
20.63
18.668
6.
6.81
1.72
0.106
35-49
23.18
32
22.022
7.16
1.88
0.152
33
38.64
26.09
26.166
8.
7-53
2.06
0.209
34
42.16
29.44
31.145
6.
7-92
2.25
0.280
35
46.12
33-30
37-152
10
8.35
2.47
0.367
36
50.59
37-75
44426
11
8.80
2.71
0.471
37
55,63
42.92
53-270
12
9-28
2.97
0.596
38
61.35
48.93
64.073
13
9.81
3-26
0.744
39
67.87
55-96
7-332
14
10.37
3-59
0.921
40
75-31
64.20
93-690
15
10.98
3-94
1.129
41
83.86
73-90
113.985
16
11.63
434
1.375
42
93-71
85-38
139-985
17
12.34
477
1.664
43
105.11
99.02
171.141
18
13.10
5-26
2.003
44
118.37
115.31
211.406
19
13-93
5.80
2.403
45
133.88
134.88
262.739
14.83
6.40
2.871
46
158.51
328.728
20
152.10
21
15.82
7.07
3-421
47
173.64
187.21
414-322
22
16.88
7.82
4,066
48
199.26
222.31
526.444
23
18.05
8.66
4,824
49
229-93
265-51
674-908
24
19-32
9.60
5-716
50
266.89
319.07
873.843
25
20.72
10.66
6.765

Shape Factors
Component
For o = 0
For o > 10
Cohesion
Aa =1+0.2
d =1+0.2
tan 45 +
Surcharge
dg = 1
=1+0.1
tan 45 +
Unit Weight
Ayn = 1
Ay = Ag
Depth Factors
Component
For = 0°
For o > 10°
Cohesion
Aed =1+0.2
Aed =1+0.2
tan 45+
Surcharge
Agd = 1
Agr = 1+0.1
tan 45 +
B
Unit Weight
Ayd = 1
Ayd = Agd
Inclination Factors
Component
Formula
Cohesion
di =
90°
Surcharge
90
B- width of the footing
D, = depth of footing
L- length of the footing
Unit Weight

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