A 1.28-kg object is suspended from a vertical spring whose spring constant is 116 N/m. (a) Find the amount (in meters, m) by which the spring is stretched from its unstrained length. (b) The object is pulled straight down by an additional distance of 0.215 m and released from rest. Find the speed with which the object passes through its original position on the way up. (a) Number i (b) Number i Units Units

Q: Homework 7, Problem 6:   A vertical spring has a length of 0.25 m when a 0.225 kg mass hangs from…

A: We have  F1 = m1 g = k(x1) = k(L1 - L0)............(1)                              and  F2 = m2g =…

Q: A 2.50-kg mass is attached to a vertical spring with spring constant, k=96.0 N/m and allowed to…

A:

Q: A 1.1-kg object is suspended from a vertical spring whose spring constant is 160 N/m. (a) Find the…

A: In the given problem, object of mass 1.1 kg is suspended vertically from the spring of spring…

Q: A pebble is launched straight up by a spring which was initially compressed by 12.0 cm relative to…

A: Calculation

Q: Suppose that an object of mass 6.7 g is hung from a vertical spring that is stretched 10.2 cm as a…

A: mg=kx    k=mgx

Q: What should be the spring constant k of a spring designed to bring a 1300 kg car to rest from a…

A: Below I have provided the solution of the given question

Q: You have a light spring which obeys Hooke's law. This spring stretches 2.34 cm vertically when a…

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Q: You have a light spring which obeys Hooke's law. This spring stretches 2.96 cm vertically when a…

A:

Q: A spring with a force constant of 5000 N/m and a rest length of 3.0 m is used in a catapult. When…

A: The total force exerted on the rock can be obtained as F=12kx2=125000N/m3.0m-1.0m2=10000N

Q: A spring hanging vertically stretches by 5.61 cm when a load of 1.34 N is attached to it. Find the…

A: Given, the spring stretched by =5.61 cm =0.0561 mload on the spring =1.34 Nwe have calculate the…

Q: The force law for a non-linear spring is F(x) = -60x1.15 N. Find the average force exerted by the…

A: This problem can be solved using the formula for the average of a function.

Q: A 65.0 kg bungee jumper uses a cord that is 7.66 m long when unstretched with a spring constant of…

A: Given:-  The mass of the bungee jumper is m = 65 kg  The length of the cord is L = 7.66 m The spring…

Q: The adjacent figure shows two configurations () of a spring (j) that is hung (les) vertically. In A,…

A: solution is given as

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A: Subpart (a): When the spring is stretched by the object, the weight of the object provides the…

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Q: A 1.70-kg mass is attached to a vertical spring with spring constant, k=93.0 N/m and allowed to…

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Q: 65.0 kg bungee jumper uses a cord that is 3.51 m long when unstretched with a spring constant of 140…

A:

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A: The given values are, m=7.13 kgk=509 N/m

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A: Given, mass of ice cube, m=50g = 5×10-2 kg slope angle, θ=30o distance due to spring compression,…

Q: A  2.3 kg mass  is attached to a horizontal spring of constant k = 578 N/m and pushed so that the…

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Q: maximum height above the point of release

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Q: A 62 kgkg driver gets into an empty taptap to start the day's work. The springs compress 2.1×10−2 mm…

A: Given,  Mass of driver m == 62 kg spring compress x = 2.1 ×10-2 m = 0.02 m The spring system obey's…

Q: When a 1 kg mass is hung on a vertical spring, it extends the spring by 0.50 m. What is the spring…

A: The weight of a hanging mass is, W=mg=1 kg10 m/s2=10 N

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Q: You have a light spring which obeys Hooke's law. This spring stretches 3.04 cm vertically when a…

A: The spring force is given as Fs=kx…

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A: mass m = 3 kg spring extends x = 2 m g = 10 m/s2

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A: Given Spring constant is k=152 N/mm Compressed distance is x=8.00 mm

Q: A block with mass of 0.85 kg is released at the top of a frictionless ramp, 1.2 m above the floor.…

A: mass = 0.85 Kg H = 1.2 m Initial potential energy = mgH   = 0.85 * 9.8 * 1.2  = 9.996 Joules…

Q: A 7.2-kg mass is hanging from the ceiling of an elevator by a spring with spring constant k = 150N/m…

A:

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.