A 20.0 g marble is fired vertically upward using a spring gun. The spring must be compressed 16.0 cm, if the marble is to just reach a target 15 m above the marble's position on the compressed spring. What is the spring constant of the spring? (Your result must be in multiplies of N/m and without decimals. Maximum of 1% of error is accepted in your answer. Take g=9.8 m/s 2.)

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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A 20.0 g marble is fired vertically upward using a spring gun. The spring must be compressed 16.0 cm, if the marble is to just reach a target 15 m above the marble's position on the compressed spring. What is the spring constant of the spring? (Your result must be in multiplies of N/m and without decimals. Maximum of 1% of error is accepted in your answer. Take g=9.8 m/s 2.)

Expert Solution
Step 1

Given: 

mass,m = 20 g 

compression in spring, y = 16 cm = 01.6 m

height, h = 15 m  

Step 2

Formula used:

The potentialenergy stored in the spring is given by 

U = 0.5 ky2

where, k is the spring constant and y is the compression in the spring. 

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