Answered: A 1.22 g sample of impure lead nitrate…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 1.22 g sample of impure lead nitrate was dissolved in 40.0 mL of distilled water and analyzed by gravimetric analysis to determine the percentage of lead by mass present. Sodium sulfate was delivered from a burette to precipitate the lead ions as lead sulfate. Sodium sulfate was added until no more precipitate was seen to form. At this point several drops of sodium sulfate were allowed to drop from the burette into the sample. The precipitate was filtered, washed and dried before been weighed. When weighed, the precipitate had a mass of 1.05 g.
Calculate the moles of lead sulfate precipitated.

Hints: answer is 3 sig figs, don't put units in. Remember leading zeros are not significant. Atomic mass of Fe is 207.2 g/mol, FW of Lead sulfate =303.26 g/mol and FW of Lead nitrate = 331.2 g/mo

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