A 1.00-L solution contains 2.50×10-4 M Cu(NO3)2 and 2.00×10-3 M ethylenediamine (en). The Kf for Cu(en)22+ is 1.00 × 1020. Cu2+(aq)+2en(aq)Cu(en)2+2(aq) Kf=[Cu(en)2+2]/[Cu2+][en]2 What is the concentration of Cu2+(aq) in the solution?
A 1.00-L solution contains 2.50×10-4 M Cu(NO3)2 and 2.00×10-3 M ethylenediamine (en). The Kf for Cu(en)22+ is 1.00 × 1020. Cu2+(aq)+2en(aq)Cu(en)2+2(aq) Kf=[Cu(en)2+2]/[Cu2+][en]2 What is the concentration of Cu2+(aq) in the solution?
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter22: An Introduction To Electroanalytical Chemistry
Section: Chapter Questions
Problem 22.12QAP: Calculate the standard potential for the half-reaction Al (C2O4)2- + 3e- Al(s ) + 2C2O42- if the...
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A 1.00-L solution contains 2.50×10-4 M Cu(NO3)2 and 2.00×10-3 M ethylenediamine (en). The Kf for Cu(en)22+ is 1.00 × 1020.
Cu2+(aq)+2en(aq)Cu(en)2+2(aq)
Kf=[Cu(en)2+2]/[Cu2+][en]2
Cu2+(aq)+2en(aq)Cu(en)2+2(aq)
Kf=[Cu(en)2+2]/[Cu2+][en]2
What is the concentration of Cu2+(aq) in the solution?
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