Let's assume Cu(OH)2 is completely insoluble, which signifies that the precipitation reaction with NaOH presented in the transition would go to completion    Cu2+ +2NaOH  Cu(OH)2 + 2Na+ if you had 0.450L solution containing 0.0240 M of Cu2+ and you wished to add enough 1.32 M NaOH  to precipitate all of the metal, what is the minimum amount of the NaOH solution you need to add? Assume that the NaOH solution is the only source of OH- for the precipitation  express the volume to three significant figures and include the appropriate units

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Let's assume Cu(OH)2 is completely insoluble, which signifies that the precipitation reaction with NaOH presented in the transition would go to completion 

 

Cu2+ +2NaOH  Cu(OH)2 + 2Na+

if you had 0.450L solution containing 0.0240 M of Cu2+ and you wished to add enough 1.32 M NaOH  to precipitate all of the metal, what is the minimum amount of the NaOH solution you need to add? Assume that the NaOH solution is the only source of OH- for the precipitation 

express the volume to three significant figures and include the appropriate units 

Expert Solution
Step 1

Given data 

Volume of Cu2+ ( V1 ) = 0.450 L

Molarity of Cu2+ ( M1 ) = 0.0240 M

Molarity of NaOH ( M2 ) = 1.32 M

Volume of NaOH ( V2 ) = ?

 

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