A 1.00 kg box has an initial speed of 8.50 m/s at the top of a frictionless ramp. At the bottom of the ramp, this box has an inelastic collision with a stationary box, which has a mass of 1.20 kg. After the collision, the two-block system moves a horizontal distance of 1.50 m, where there is friction. After this, it goes through circular motion as it moves up a frictionless semi- circular ramp. At location A shown on the semi-circular ramp, the speed is 1.50 m/s. Find the magnitude of the normal force at 4 and ø. Do not solve this problem by finding the horizontal acceleration of the blocks when they are on the friction part. VA = 1.50 m/s --------- )ø = ? 8.50 m/s no friction on semi- circular ramp 60.0 cm H =0.150 R= 50.0 cm 1.50 m

icon
Related questions
Question
**Physics Problem: Box Collision and Circular Motion on a Ramp**

A 1.00 kg box has an initial speed of 8.50 m/s at the top of a frictionless ramp. At the bottom, it collides inelastically with a stationary box of mass 1.20 kg. After the collision, the combined system moves horizontally across a surface with friction, covering a distance of 1.50 m. Subsequently, it moves up a frictionless semi-circular ramp. At point \( A \) on this semi-circular ramp, the speed is 1.50 m/s.

**Objective:** Find the magnitude of the normal force at point \( A \) and the angle \(\phi\).

**Constraints:** Do not solve this problem by determining the horizontal acceleration of the blocks in the frictional region.

**Illustration Details:**

- **Initial Setup:** 
  - The ramp height is 60.0 cm and frictionless.
  - Initial speed of the box is 8.50 m/s.

- **Collision:**
  - A second, stationary box (mass 1.20 kg) is at the ramp's bottom.

- **Frictional Surface:**
  - The coefficient of kinetic friction (\(\mu_k\)) is 0.150.
  - The combined system travels 1.50 m horizontally on this surface.

- **Semi-Circular Ramp:**
  - The ramp has a radius \( R = 50.0 \) cm.
  - At point \( A \), the speed is 1.50 m/s.
  - The ramp is frictionless in this region.

By analyzing momentum, energy conservation, and forces acting on the blocks, you are tasked with finding the normal force at \( A \) and \(\phi\).
Transcribed Image Text:**Physics Problem: Box Collision and Circular Motion on a Ramp** A 1.00 kg box has an initial speed of 8.50 m/s at the top of a frictionless ramp. At the bottom, it collides inelastically with a stationary box of mass 1.20 kg. After the collision, the combined system moves horizontally across a surface with friction, covering a distance of 1.50 m. Subsequently, it moves up a frictionless semi-circular ramp. At point \( A \) on this semi-circular ramp, the speed is 1.50 m/s. **Objective:** Find the magnitude of the normal force at point \( A \) and the angle \(\phi\). **Constraints:** Do not solve this problem by determining the horizontal acceleration of the blocks in the frictional region. **Illustration Details:** - **Initial Setup:** - The ramp height is 60.0 cm and frictionless. - Initial speed of the box is 8.50 m/s. - **Collision:** - A second, stationary box (mass 1.20 kg) is at the ramp's bottom. - **Frictional Surface:** - The coefficient of kinetic friction (\(\mu_k\)) is 0.150. - The combined system travels 1.50 m horizontally on this surface. - **Semi-Circular Ramp:** - The ramp has a radius \( R = 50.0 \) cm. - At point \( A \), the speed is 1.50 m/s. - The ramp is frictionless in this region. By analyzing momentum, energy conservation, and forces acting on the blocks, you are tasked with finding the normal force at \( A \) and \(\phi\).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 6 steps with 6 images

Blurred answer
Similar questions