A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F = (2.1t )i N (witht in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a = 0 for 0 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface?

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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IS Halliday, Fundamentals of Physics, 11e
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Chapter 06, Problem 093
(2.1).
N (with t in seconds) is applied to the box. The acceleration of the box
A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F=
as a function of time t is given by a = 0 for 0 <t< 2.8 s and a = (2.10t - 2.4)i m/s² for t > 2.8 s. (a) What is the coefficient of static friction between the box and
the surface? (b) What is the coefficient of kinetic friction between the box and the surface?
(a) Number
Units
(b) Number
Units
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Transcribed Image Text:IS Halliday, Fundamentals of Physics, 11e Help | System Announcements PRINTER VERSION 1 BACK NEXT Chapter 06, Problem 093 (2.1). N (with t in seconds) is applied to the box. The acceleration of the box A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F= as a function of time t is given by a = 0 for 0 <t< 2.8 s and a = (2.10t - 2.4)i m/s² for t > 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface? (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER 7:13 PM re to search ENG 4/4/2021 17 pause break pgdn prt sc insert delete Pgup %23 3 4 backspace
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