A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F = (2.1r )i N (with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a = 0 for 0 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface? (a) Number Units This answer has no units v (b) Number UnitsTThis answer has no units v

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Chapter1: Units, Trigonometry. And Vectors
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Z Your answer is partially correct. Try again.
A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F = ( 2.1t )i
N (with t in seconds) is applied to the box. The acceleration of the box
as a function of time t is given by a = 0 for 0 <t< 2.8 s and a = (2.10t - 2.4)i m/s for t> 2.8 s. (a) What is the coefficient of static friction between the box and
the surface? (b) What is the coefficient of kinetic friction between the box and the surface?
(a) Number
UnitsT This answer has no units v
(b) Number
UnitsTThis answer has no units v
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Transcribed Image Text:Z Your answer is partially correct. Try again. A 1.0 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F = ( 2.1t )i N (with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a = 0 for 0 <t< 2.8 s and a = (2.10t - 2.4)i m/s for t> 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface? (a) Number UnitsT This answer has no units v (b) Number UnitsTThis answer has no units v Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER to search 10:48 PM ENG 4/4/2021 prt sc home pause insert delete 13) break %23 backspace 3. 4 F
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