A 1 kg mass on a frictionless inclined surface is connected to a 2 kg mass as shown. The pulley is mass less and frictionless. The 2 kg mass acted on by an upward force F = 6Newton has a downward acceleration of 5.5 m/s². What is the tension T in the connecting cord? What is angleß? 1kg 2kg F

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A: Solution:-

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A: Solution attached in the photo

Q: Which of the following forces act on the block parallel to the incline?

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A: This problem can be solved using Newton's second law of motion.

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A: The solution for this question has been solved below..

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Q: F 60 3.0 kg 10 kg

A: Given: Mass mA = 10 kg. Mass mB = 3.0 kg. Force F = 80 N.

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Q: 42° b J a d 30 25° m

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Q: Answers: FA= i @ 190 mm 195 mm 190 mm 6.8 kN 3.1 KN ! KN

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A: x component of force Fx   = F1 cos θ   +   F2 cos θ  +F3   cos θFx   =20 cos 30   +  40 cos 140  +30…

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A: The total mass is  3+3=6 kg The resultant force is F=ma=6×0.5=3 N The external force applied is 20…

Q: d surface

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Q: LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static…

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: