A 0.9092-g sample of a wheat flour was ana-lyzed by the Kjeldahl procedure. The ammoniaformed was distilled into 50.00 mL of 0.05063M HCI; a 7.46-mL back-titration with 0.04917M NAOH was required. Calculate the percent-age of protein in the flour.9-22.

Given that: Mass of wheat flour sample = 0.9092 g Molarity of HCI = 0.05063 M Volume of HCI = 50.0…

A 0.9092-g sample of a wheat flour was ana- lyzed by the Kjeldahl procedure. The ammonia formed was distilled into 50.00 mL of 0.05063 M HCl; a 7.46-mL back-titration with 0.04917 M NAOH was required. Calculate the percent- age of protein in the flour.

A 0.9092-g sample of a wheat flour was ana- lyzed by the Kjeldahl procedure. The ammonia formed was distilled into 50.00 mL of 0.05063 M HCl; a 7.46-mL back-titration with 0.04917 M NAOH was required. Calculate the percent- age of protein in the flour.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: A 15.00 mL sample of hard water was titrated with a 0.0150 M EDTA solution. The titration required…

A: The objective of this question is to calculate the total hardness concentration of the water sample…

Q: A 400 mg sample of a 600 mg tablet is dissolved in 60 mL of 0.3 M H2SO4 and combined with 2 g of…

Q: . Titration of Ca²+ and Mg²+ in a 50.00-mL hard water sample required 23.65 mL of 0.01205 M EDTA. A…

A: A question based on environmental pollution that is to be accomplished.

Q: A quantitative analysis for ethanol, C2H60, is accomplished by a redox back titration. Ethanol is…

Q: Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a…

A: Given,The volume of KIO3 used = 22.84 ml = 0.02284 L ( 1L = 1000 ml) Concentration of KIO3 = 0.0100…

Q: 40.00 mL of unknown calcium hydroxide solution is titrated with 0.400 M standard nitric acid…

Q: The titration of 100.mL of 0.100 M NH3 (in the flask) with 0.200 M HCL (in the burette) was carried…

A: In the given scenario, we conduct a titration experiment between a weak base, ammonia (NH3), and a…

Q: For breakfast, the nihilistic Rick Sanchez ate 100 g of cereal mixed with 20 g of milk. A 1.500 g…

A: Given: The molar mass of N (nitrogen) is 14.07 g/mol. For cereal: The amount of cereal consumed is…

Q: 150.0 mL of 0.2105 M HNO3 was added in excess to 1.3415 g CaCO3 (100.09 g/mol). The excess acid was…

A: Given - volume of HNO3 = 150.0 mL Molarity of HNO3 = 0.2105 M Mass of CaCO3…

Q: 30.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein…

A: Given: Volume of H2SO4, V1 = 30.00mL Volume of phenolphthalein, V2 = 37.77mL Molarity of…

Q: A 1.0325-g sample of a wheat flour was analyzed by the Kjeldahl procedure. The ammonia formed was…

A: The excess of HCl used can be calculated using, Millimoles of NaOH = millimoles of HCl Getting this…

Q: Calculate the number of moles Na2C2O4 used in each of the three samples. Calculate the concentration…

Q: A student determined the concentration of copper by ion exchange. He obtained the following results:…

Q: A 25.0-mL aliquot of vinegar was diluted to 250 mL in a volumetric flask. Titration of 50.0-mL…

A: The balanced reaction of acetic acid (vinegar) and sodium hydroxide is: CH3COOH + NaOH → CH3COONa +…

Q: The titration of 86.9 mL of an unknown concentration H3PO4 solution requires 94.6 mL of 0.086 M KOH…

A: Volume of H3PO4 = 86.9 ml ...Or because 1L = 1000 ml ...so, = 86.9 ml × (1L / 1000 ml ) =…

Q: A 50.0 mL solution of Ca(OH)₂ with an unknown concentration was titrated with 0.340 M HNO₃. To reach…

A: The reaction of HNO3 and Ca(OH)2 is, In the given reaction moles ratio between HNO3 and Ca(OH)2 is…

Q: A sample containing calcium was analyzed by gravimetry, converting all calcium to calcium oxalate…

A: Given that the precipitate is calcium oxalate monohydrate.

Q: A student prepares a weak acid solution by dissolving 0.2400 g HZ to give 100. mL solution. The…

A: We have to predict the molar mass, effect on molar mass.

Q: Bay Water Titration The concentration of Cl- in ocean water is about 500-600 mM. The baywater is…

A: In the provided scenario, a chemical analysis is performed to determine the chloride ion…

Q: 5 The amount of ascorbic acid, C6HSO6, in orange juice was determined by oxidizing the ascorbic acid…

A: The amount of ascorbic acid, C6H8O6, in orange juice was determined by oxidizing the ascorbic acid…

Question

A 0.9092-g sample of a wheat flour was ana-
lyzed by the Kjeldahl procedure. The ammonia
formed was distilled into 50.00 mL of 0.05063
M HCI; a 7.46-mL back-titration with 0.04917
M NAOH was required. Calculate the percent-
age of protein in the flour.
9-22.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

ANSWER

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

A 1.43 x 10-4 L solution of 45.7 mg/mL protein was analyzed using the Kjeldahl procedure. After digestion of the protein, the liberated NH3 was collected in 9.80 mL of 0235 M HCl. The unreacted acid required 10.75 mL of a standard solution of 0.0149 M NaOH for complete titration. Calculate the weight percent of nitrogen in the protein. (Molar mass N = 14.00674 g/mol)
A 1.000-g sample of a sweetening agent containing soluble Saccharin (MM=205.17g/mol) was analyzed using the Volhard method as follows: Step 1: Sample was dissolved in distilled water and treated with 10.0 mL of 0.05M AgNO3. Saccharin-Na + Ag+ → Saccharin-Ag (s) + Na+ Step 2: The solid, Saccharin-Ag (s), formed was filtered off and washed with water. The filtrate and washing were collected quantitatively. Step 3: Titration of the filtrate and washings required 4.6 mL of 0.04M KSCN. KSCN + Ag + → AgSCN (s) + K+ Calculate weight % saccharin in the sweetening agent sample. could you type it out, please
2. Using the procedure described in this module, a student determined the percent KHP in an impure sample of KHP. A 3.150-g sample of impure KHP required 41.50 mL of 0.1352M NaOH solution for titration. (a) Calculate the number of moles of NaOH required for the titration. (b) Calculate the number of moles of KHP present in the impure sample of KHP. (c) Calculate the number of grams of KHP present in the impure sample. (d) Calculate the percent of KHP in the impure sample, using Equation 8. Equation 8: percent KHP in the impure sample, % = ( mass of KHP in the sample,g/ mass of sample analyzed, g) (100%)
A sample of alfalfa meal weighing 2.0 g is analyzed by Kjeldahl method for the percentage of nitrogen. The liberated NH3 is caught in a solution of H3BO3, and 8.23 ml of HCl are required in the subsequent titration. A sample of pure (NH4)2SO4 (132.12) weighing 0.61 g is treated with excess NaOH and the liberated NH3 (17.04) is also caught in H3BO3. The resulting solution requires 20 ml of the acid for titration. Calculate the percentage of protein in the sample using 6.25 as the factor.
4) A 25.00-mL sample of vinegar is diluted with deionized to 100.0 mL. Then a 10.00-mL aliquot (portion) of the dilute vinegar solutionis titrated with 0.1055 M NaOH solution using phenolphthalein as theindicator. (a) If 19.60 mL of the base solution is required to reach the end-point, calculate the molar concentration of acetic in dilute vinegar solution. (b) What is the molar concentration of acetic acid in the original (undiluted) vinegar? The acid-base reaction occurs as follows: HC2H3O2(aq) + NaOH(aq) --> H2O(l) + NaC2H3O2(aq)
25.00 mL of a solution containing KIO4 is treated with excess potassium iodide. IO4- + 8H+ + 7I- → 4I2 + 4H2O The resulting solution is titrated with 0.15 M sodium thiosulfate pentahydrate. The average titre was 21.76 mL. I2 + 2S2O32- → 2I- + S4O62- What is the concentration of the sodium thiosulfate solution as a percentage (w/v)
In the titration of 25.00 mL of a water sample, it took 20.590 mL of 3.150x 10−3 M EDTA solution to reach the endpoint. The total hardness is due to one or a combination of Ca2+, Mg2+, and Fe2+ in your sample. It is convenient to express this hardness as though it was entirely due to Ca2+. Making this assumption, determine the number of moles of Ca2+ present in the bottled water sample titrated. (enter your answer with 3 significant figures)
A solution of malonic acid (H2C3H2O4) with a known concentration of 0.500 M H2C3H2O4 is tirated with a 0.255 M KOH solution. How many mL of KOH are required to reach the second equivalence point with a starting volume of 60.0 mL H2C3H2O4, according to the following balanced chemical equation: H2C3H2O4 + 2 KOH---> K2C3H2O4 + 2 H2O