A 0.2985 g sample of an antibiotic powder was dissolved in HCl and the solution diluted to 100.0 mL. A20.00 ml aliquot was transferred to a flask and followed by 25.00 ml of 0.01886 M KBRO3. An excess ofKBr was added to form Br2, and the flask was stoppered. After 10 min, during which time the Br2brominated the sulfanilamide, an excess of KI was added. The liberated iodine titrated with 12.88 ml of0.1235 M sodium thiosulfate. Calculate the percent sulfanilamide (NH2C,H4SO2NH2) in the powder.Bro, + 5Br + 6H*3Br, + 3H,0NH2NH2Br.Br+ 2B12+ 2H++ 2BrSO,NH2SO,NH2sulfanilamideBr, + 512Br + 12excess2 + 25,0,-25,0,2 + 21--MM: NH2C6H4SO2NH2 = 172.21KBRO3= 167.00KBr119.00

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Answered: A 0.2985 g sample of an antibiotic…

Chemistry

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

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Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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